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Bunuel

Right angle ABC is inscribed in a quarter of a circle, as shown above. What is the length of line segment DC ?

A. 3
B. 4
C. 5
D. 7
E. 15

Attachment:
Screenshot 2022-07-15 at 10.19.39 PM.png
Screenshot 2022-07-15 at 10.19.39 PM.png [ 228.29 KiB | Viewed 3864 times ]

Steps -
1. Find AC using the Pythagorean theorem.
AC = 25
2. \(\triangle ACE\) is an isosceles triangle. Therefore, \(CE = AC = 25\).
3. \(BE = 25 + 7 = 32\)
6. From Right angled \(\triangle ABE\), AE = 40. Hence, Radius of Circle is 20.
7. From Right angled \(\triangle AOC\), CO = 15. Hence, \(DC = 20 - 15 = 5\).

Hence, the answer is C.
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Few inferences that we can make -

1) As \(\angle ABC is 90\), if we extend BC to form BX, AX will be the diameter of the circle as shown in figure attached.
2) Also, the triangles formed \(\triangle XOC\) is similar to \(\triangle XBA\)
3) CA = CX

CA = 25 (we can use triplet 7 - 24 - 25)

Therefore CX = 25
BX = 7+25 = 32

\(AX^2\) = \(AB^2\) + \(BC^2\)

\(AX^2\) = \(24^2\) + \(32^2\)

\(AX^2\) = 576 + 1024 = 1600

AX = 40

AO = OX = 20

Using similarity of triangle

\(\frac{OX}{XB}\) = \(\frac{CO}{BA}\)

CO = \(\frac{OX * BA }{XB}\)

CO = \(\frac{20 * 24}{32}\)

CO = 15

DC = 20 - 15 = 05

IMO C
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Screenshot 2022-07-16 144553.png
Screenshot 2022-07-16 144553.png [ 57.88 KiB | Viewed 1539 times ]

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