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Let number of shirt only purchases be s and cap only purchases be c

We know T = group of only 1 item + both + none
T = 260 and none = 0
Both = 90
We intend to double count the shirt and cap purchases as 2 articles were bought by the 90 fans
s+c+90+90=260
s+c=80

Total shirts = s+90 =?

Need to know s or c to calculate the total shirts sold

Statement 1
If 50 didn't buy a shirt, they bought a cap
c=50
Sufficient

Statement 2
c+90=140
c=50
Sufficient

Answer D
Bunuel
A football club’s memorabilia shop sells only shirts and caps. On a weekend, the shop sold 260 memorabilia items, with each fan buying either one shirt, one cap, or one of each. If 90 fans bought both a shirt and a cap, how many shirts did the shop sell?

(1) 50 fans did not buy a shirt.
(2) 140 fans bought a cap.


Gentle note to all experts and tutors: Please refrain from replying to this question until the Official Answer (OA) is revealed. Let students attempt to solve it first. You are all welcome to contribute posts after the OA is posted. Thank you all for your cooperation!
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Let number of single sold shirts be s and caps be c
s+c+90+90=260
s+c=80

Need to know s or c to calculate the total shirts sold, which will be s+90

Statement 1
If 50 didn't buy a shirt, they bought a cap
c=50
Sufficient

Statement 2
c+90=140
c=50
Sufficient

Answer D
Bunuel
A football club’s memorabilia shop sells only shirts and caps. On a weekend, the shop sold 260 memorabilia items, with each fan buying either one shirt, one cap, or one of each. If 90 fans bought both a shirt and a cap, how many shirts did the shop sell?

(1) 50 fans did not buy a shirt.
(2) 140 fans bought a cap.


Gentle note to all experts and tutors: Please refrain from replying to this question until the Official Answer (OA) is revealed. Let students attempt to solve it first. You are all welcome to contribute posts after the OA is posted. Thank you all for your cooperation!

The answer is correct. However, there is a problem with the solution.
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Thanks for pointing it out Bunuel. Can you please share what is the problem? Is it because I haven't used sets strategy to solve this, like t = s+c+b+n, (given s and c are shirt only and cap only purchases)?

Bunuel
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Let number of single sold shirts be s and caps be c
s+c+90+90=260
s+c=80

Need to know s or c to calculate the total shirts sold, which will be s+90

Statement 1
If 50 didn't buy a shirt, they bought a cap
c=50
Sufficient

Statement 2
c+90=140
c=50
Sufficient

Answer D
Bunuel
A football club’s memorabilia shop sells only shirts and caps. On a weekend, the shop sold 260 memorabilia items, with each fan buying either one shirt, one cap, or one of each. If 90 fans bought both a shirt and a cap, how many shirts did the shop sell?

(1) 50 fans did not buy a shirt.
(2) 140 fans bought a cap.


Gentle note to all experts and tutors: Please refrain from replying to this question until the Official Answer (OA) is revealed. Let students attempt to solve it first. You are all welcome to contribute posts after the OA is posted. Thank you all for your cooperation!

The answer is correct. However, there is a problem with the solution.
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Thanks for pointing it out Bunuel. Can you please share what is the problem? Is it because I haven't used sets strategy to solve this, like t = s+c+b+n, (given s and c are shirt only and cap only purchases)?


If I understand your solution correctly, you concluded that 50 caps were sold. But we're told that 90 fans bought both a shirt and a cap, so at least 90 caps must have been sold. How is it possible, then, for only 50 caps to be sold?

I'll post the official solution shortly. Let's also see what others come up with.
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You are absolutely right, and s and c are single purchase numbers. I had mentioned that while assuming the variables but it might not have been that clear with the wording I used. Let me include more commentary
Bunuel
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Thanks for pointing it out Bunuel. Can you please share what is the problem? Is it because I haven't used sets strategy to solve this, like t = s+c+b+n, (given s and c are shirt only and cap only purchases)?


If I understand your solution correctly, you concluded that 50 caps were sold. But we're told that 90 fans bought both a shirt and a cap, so at least 90 caps must have been sold. How is it possible, then, for only 50 caps to be sold?

I'll post the official solution shortly. Let's also see what others come up with.
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Bunuel
A football club’s memorabilia shop sells only shirts and caps. On a weekend, the shop sold 260 memorabilia items, with each fan buying either one shirt, one cap, or one of each. If 90 fans bought both a shirt and a cap, how many shirts did the shop sell?

(1) 50 fans did not buy a shirt.
(2) 140 fans bought a cap.


Gentle note to all experts and tutors: Please refrain from replying to this question until the Official Answer (OA) is revealed. Let students attempt to solve it first. You are all welcome to contribute posts after the OA is posted. Thank you all for your cooperation!
Given, each fan buys a shirt , or a cap or both. So, none = 0

Lets consider the two set venn diagram



let the common be x

Given x = 90

Set 2, which denotes shirt alone = s-x

set1, which denotes cap alone = c-x

s-x + x + c-x = 260

s + c = 260+x = 260+ 90 = 350

s+c = 350.

We need to find: Shirts sold

statement 1:

(1) 50 fans did not buy a shirt.

50 did not buy shirt, so 50 must have bought caps. As none = 0

x denotes both cap and shirt. So, 50 will not come for x.

c-x = 50. Thus, c = 50+x = 50+ 90 = 140.

we can find the number of shirts sold.

Shirt alone will be 260-140 = 120

Total shirts = 120+90 = 210. Hence, Sufficient

(2) 140 fans bought a cap.

This statement, is same as what we have deduced from statement 1.

Shirt alone will be 260-140 = 120

Total shirts = 120+90 = 210. Hence, Sufficient

Hence, Option D
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Bunuel
A football club’s memorabilia shop sells only shirts and caps. On a weekend, the shop sold 260 memorabilia items, with each fan buying either one shirt, one cap, or one of each. If 90 fans bought both a shirt and a cap, how many shirts did the shop sell?

(1) 50 fans did not buy a shirt.
(2) 140 fans bought a cap.


Gentle note to all experts and tutors: Please refrain from replying to this question until the Official Answer (OA) is revealed. Let students attempt to solve it first. You are all welcome to contribute posts after the OA is posted. Thank you all for your cooperation!

Given:

The shop sold 260 memorabilia items.

Possible purchases
1. Only Caps
2. Only Shirts
3. Shirts and Caps

Question:

Only Shirts = ?

Statement 1

(1) 50 fans did not buy a shirt.

The premise states that every fan bought atleast one item. Hence, if 50 fans did not buy a shirt, they must have boughts only caps.

Only Shirts = 260-(50+90) = 120

The statement alone is sufficient. We can elimiante options B, C and E

Statement 2

(2) 140 fans bought a cap.

The premise states that every fan bought atleast one item, and we also know that 90 fans bought both a shirt and a cap. Therefore we can conclude that 50 fans bought only caps.

Only Shirts = 260-(50+90) = 120

The statement alone is sufficient.

Option D
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