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23 Apr 2026, 19:00
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
69% (02:23) correct
31%
(02:33)
wrong
based on 48
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A guest house had food for 60 days for an occupancy of 100 guests. After 20 days, 50 guests left and 20 new guests joined; if the average diet of the new guests is 50% higher than the average diet of the earlier guests, how many more days will the supply last?
A. 45
B. 50
C. 60
D. 70
E. 80
A. 45
B. 50
C. 60
D. 70
E. 80
23 Apr 2026, 22:24
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60*100*x = 1.
x = 1/6000.
In 20 days:
20*100*1/6000 = 1/3.
Which means 1/3rd of the supply is complete. Remaining = 2/3.
Considering 50 leave and the new 20 have 1.5x more intake:
x[50*1/6000 + 20*(1.5/6000)] = 2/3.
Solving for x:
= 50.
Answer: Option B
x = 1/6000.
In 20 days:
20*100*1/6000 = 1/3.
Which means 1/3rd of the supply is complete. Remaining = 2/3.
Considering 50 leave and the new 20 have 1.5x more intake:
x[50*1/6000 + 20*(1.5/6000)] = 2/3.
Solving for x:
= 50.
Answer: Option B
ExpertsGlobal5
24 Apr 2026, 08:21
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Quick solution (copy-paste ready):
Total food = 100 times 60 = 6000 units
Used in 20 days = 100 times 20 = 2000 units
Remaining = 6000 - 2000 = 4000 units
New consumption:
50 old guests → 50 times 1 = 50
20 new guests → 20 times 1.5 = 30
Total = 80 units/day
Remaining days = 4000 ÷ 80 = 50
Final Answer: B. 50 days
Total food = 100 times 60 = 6000 units
Used in 20 days = 100 times 20 = 2000 units
Remaining = 6000 - 2000 = 4000 units
New consumption:
50 old guests → 50 times 1 = 50
20 new guests → 20 times 1.5 = 30
Total = 80 units/day
Remaining days = 4000 ÷ 80 = 50
Final Answer: B. 50 days
