If smallest possible number is 0, then the largest number of that set must be 16.
Is that possible? No.
Why? Because right side of median you are not increasing the value of mean at all.
Left side you have a -16 as compared to the mean and u need a +16 to compensate right side of median to match the average of 16.
The lowest possibility is 2:
Why?
When we keep 2, and every other value till median to be 16,
then we have a -14 difference to the avg/median and the largest value here will be 18.
Keeping every value right side of median to 18 we have a +14 right side, -14 left side because of 2.
Both deviations cancel out which means average matches as well. Mode matches too as there is one more 16 than 18.
Highest value is taken on similar principles. You need to do the exact opposite as the first case.
Take 2*7 = +14 deviation to the right of median = 16+14 = 30.
Lowest value becomes 14 now, and using deviation principles we again see that it is valid.
Symmeyrical to the first case except we aim for highest values here.
So difference between highest and lowest = 30-2 =
28.
Hope it helps.
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These stats problems are quite tricky to be fair, what do you think is the genuine difficulty of this
kevincan? Definitely seems 700+ range.
ankushsambare
Hi
kevincan ,
Can you please check the answer?
I am getting (E) 32:
mean = 16 → total sum = 256
range = 16 → max = min + 16
median = 16 → 8th and 9th terms are 16
mode = 16 → 16 appears most often
to find extreme possible values across all valid sets:
make minimum as small as possible
make maximum = minimum + 16
and keep just enough 16s (at least 3) to maintain median and mode
balancing the sum, you can push:minimum down to 0
→ then maximum = 16 above shifts across constructions up to 32
so across all valid sets:
smallest possible member = 0
largest possible member = 32
Difference = 32