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Bunuel
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n = 8p + 3 (possible values = 11, 19, 27, 35)
n = 5q + 2 (possible values = 7, 12, 17, 22, 27)

Thus, smallest possible value of n = 27
27/6 gives 3 as remainder.

answer is D.
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Let us assume n = 8k + 3, and 5m+2.
Both the expressions are equal to n, hence 8k+3 = 5m+2
5m = 8k+1,
We need to find the smallest value of m and k for this equation to be valid, which gives us m=5, k=3, giving n = 27.
Now, when 27/6, the remainder is 3.
Therefore, the correct answer is D. 3
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Correct Answer: D (3)

GIVEN:
n = 8k + 3
n = 5m + 2
Target: Remainder when smallest n is divided by 6

CALCULATION:
List values of n = 8k + 3:
n = 3 => 3 mod 5 = 3
n = 11 => 11 mod 5 = 1
n = 19 => 19 mod 5 = 4
n = 27 => 27 mod 5 = 2 (MATCH)

Smallest n = 27

27 / 6 = 4 remainder 3.

Conclusion: Answer Choice D (3).

Bunuel
When the positive integer n is divided by 8, the remainder is 3, and when n is divided by 5, the remainder is 2. What is the remainder when the smallest possible value of n is divided by 6?

A. 0
B. 1
C. 2
D. 3
E. 4


Source: Math Revolution

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