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Darden2010
Joined: 30 Mar 2007
Last visit: 22 Jul 2020
Posts: 493
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Schools: Darden '15
GMAT Date: 12-07-2011
Updated on: 24 Jun 2008, 10:18
Originally posted by Darden2010 on 20 Nov 2007, 15:24.
Last edited by Darden2010 on 24 Jun 2008, 10:18, edited 1 time in total.
Last edited by Darden2010 on 24 Jun 2008, 10:18, edited 1 time in total.
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20 Nov 2007, 15:32
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C
P=a^4-b^4=(a^2-b^2)(a^2+b^2)
1. (a^2-b^2)=16 ==> P=16*(16+2b^2) insuff
2. (a+b)=8 ==> P=8*(a-b)(a^2+b^2) insuff
1&2. (a^2-b^2)=16
(a+b)(a-b)=16 ==> (from 2nd statement) 8*(a-b)=16 ==>a-b=2
a-b=2
a+b=8
a=5,b=3
suff.
P=a^4-b^4=(a^2-b^2)(a^2+b^2)
1. (a^2-b^2)=16 ==> P=16*(16+2b^2) insuff
2. (a+b)=8 ==> P=8*(a-b)(a^2+b^2) insuff
1&2. (a^2-b^2)=16
(a+b)(a-b)=16 ==> (from 2nd statement) 8*(a-b)=16 ==>a-b=2
a-b=2
a+b=8
a=5,b=3
suff.
20 Nov 2007, 15:32
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(C) for me 
a^4 - b^4
=(a^2 - b^2)*(a^2 + b^2)
Stat 1
a^2 - b^2 = 16
Implies that:
a^4 - b^4 = 16*(a^2 + b^2)... We have no clue about the value of (a^2 + b^2).
INSUFF.
Stat 2
a + b = 8
We cannot know a^4 - b^4
INSUFF.
Both (1) and (2)
o a + b = 8
o a^2 - b^2 = 16 = (a+b)*(a-b)
implies that:
o a-b = 2
o a+b =8
2 different equations with 2 variables : we can have a (=5) and b(=3), so a^4 - b^4.
a^4 - b^4
=(a^2 - b^2)*(a^2 + b^2)
Stat 1
a^2 - b^2 = 16
Implies that:
a^4 - b^4 = 16*(a^2 + b^2)... We have no clue about the value of (a^2 + b^2).
INSUFF.
Stat 2
a + b = 8
We cannot know a^4 - b^4
INSUFF.
Both (1) and (2)
o a + b = 8
o a^2 - b^2 = 16 = (a+b)*(a-b)
implies that:
o a-b = 2
o a+b =8
2 different equations with 2 variables : we can have a (=5) and b(=3), so a^4 - b^4.
