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I liked this question.

You must be aware of a formula of finding sum of angles of a polygon.
Its (n-2)*180 where n is number of sides the polygon has.

This ways, sum of angles in pentagon = 540.
We have 5 angles. So each angle of 540/5 = 108 degrees.

Now picture the 5 small isosceles angles the star makes at its 5 points.

Let’s take one of that triangle. Say at point x.
Now, x + (180 - 108) + (180 - 108) = 180 ---> 3 points of isosceles triangle.

Solving this x = 36.
And V+X+Y+Z+W = 36*5 = 180
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let p,q,r,s ant be the angles of the polygon in the center.

=>p+q+r+s+t = 3(180) = 540 ( as sum of the angles in a polygon with n sides = (n-2)*180 )

then for each of the 5 triangles we will have

x+ 180-p+180-t = 180
y +180-p+180-q = 180
z+180-q+180-r = 180
w+180-r+180-s = 180
v+180-s+180-t = 180

adding all the above 5 equations we have
x+y+z+w+v = 180
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Because this is drawn to scale and the answer choices are quite far apart one can quite simply estimate the answer.

(I agree this won't always work but when it does it saves precious time.)
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