Less than half of a committee that is to be formed out of

Question

Less than half of a committee that is to be formed out of certain group, are to be men. If there are 100 possible ways of forming the committee, then the number of men in the committee can be,

A. 2
B. 3
C. 4
D. 5
E. cannot be determined

shanmugamgsn · Answer

100 possible ways means. 
 T^2  = 100 
so T= 10 
So there are of total 10 members, making out of 100 members different ways.

Less than half of a committee that is to be formed out of certain group, are to be men. 
m <  1/2 T 
m < 2.5 
So m will be 2

Guys I have a doubt in this. If my abve method is correct, 100 possible ways means will give 10 by means of   combinations or permutations   ?

SVaidyaraman · Answer

1. Let there be m men and w women out of which the committee is formed.
2. mCn * wCr = 100, where n is the number of men chosen and r is the number of women chosen
3. The possible products for LHS of (2) are, 100 * 1, 50 * 2, 25 * 4, 20 * 5, 10 * 10
4. Since the number of women is greater than the number of men, the first three products in (3) can be rejected as they would not satisfy this condition.
5. In the case of the fourth product, 20 * 5 may be given by 6C3 * 5C1. Though this may satisfy the condition with 3 women and 1 man, 1 man is not in the choices given.
6. The last product 10 * 10 may be given by 5C2 * 5C3 with 2 men and 3 women. This satisfies the condition and also 2 men is one of the choices given.

Therefore the answer is choice A.

Perhaps · Answer

" the first three products in (3) can be rejected as they would not satisfy this condition. " could not understand that y these 3 products r not satisfying the condition.

as 100*1 can mean that there are 100 women and 1 man....50*2 means that 50 women and 2 men....25*4 means that 4 men 25 women..... my other concern is how to calculate quickly that 20 is 6C3 or 10 is 5C2. Please help me on this...Thanks

SVaidyaraman · Answer

100 can mean only 100 C1, as you are selecting 1 woman out of 100 women. So you are selecting only 1 woman. 1 can mean only nCn and so you are selecting at least one man. But this does not satisfy the condition that the committee should have fewer men than women. Similarly other two cases can be ruled out.

I really do not know any short cut for figuring out how 20 is 6C3 and so on but you can try to remember them for smaller values.

Archit3110 · Answer

another way of doing it is by using answer options
given that men will be less than half and total ways is 100
nCr*nCr-1 =100

if r=3 then n will be least 7
7c3*7c4 is a large number >100 so no
if r=2 then n will be least 5
5c2*5c3 = 100
option A is correct

Regor60 · Answer

This appears to be a faulty question.

Assuming a pool of 2 men and 100 women and building a committee of 2 Men and 99 women, there are 100 ways of building such a committee, but not 100 ways to do so when the committee comprises 3,4 or 5 men.

On the other hand, assuming a pool of 4 men and 100 women, there are also 100 ways of building a committee of 4 men and 99 women but not 100 ways to build a committee comprising 2, 3 or 5 men.

So answer choices A and C both work in which case answer E appears to be most appropriate.

Less than half of a committee that is to be formed out of

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