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20 Nov 2018, 18:11
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Since k passes through the origin (0,0), the y-intercept will be 0.
\(y = mx + b\)
\(0 = m0 + b\)
\(0 = b\)
Also, since the slope is 2, our equation becomes:
\(y = mx + b\)
\(y = 2x + 0\)
Finally, x and y are found by plugging in the values for each point then solving for the unknown variable.
\((3,y)\)
\(y = 2(3) + 0\)
\(y = 6\)
\((x,4)\)
\(4 = 2x + 0\)
\(2 = x\)
\(x+y\)
\(2+6 = 8\)
\(y = mx + b\)
\(0 = m0 + b\)
\(0 = b\)
Also, since the slope is 2, our equation becomes:
\(y = mx + b\)
\(y = 2x + 0\)
Finally, x and y are found by plugging in the values for each point then solving for the unknown variable.
\((3,y)\)
\(y = 2(3) + 0\)
\(y = 6\)
\((x,4)\)
\(4 = 2x + 0\)
\(2 = x\)
\(x+y\)
\(2+6 = 8\)
26 Oct 2019, 06:20
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Hi EMPOWERgmatRichC
Could you please help me clear my small doubt?
So if I am getting this correctly, it's not true that a line passing through the origin will not always have a eq of typical y=x (for + slope) and y=-x (for - slope) it can be y= 2x as well?
Thank you,
Dablu
Quote:
Could you please help me clear my small doubt?
So if I am getting this correctly, it's not true that a line passing through the origin will not always have a eq of typical y=x (for + slope) and y=-x (for - slope) it can be y= 2x as well?
Thank you,
Dablu
26 Oct 2019, 19:21
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Hi gurudabl,
When a line is written in slope-intercept 'format' (Y = MX + B) if there is NO "B" value, then the line moves through the Origin (re: the point 0,0). The slope (re: the "M") has no impact on that, meaning that as long as B=0, then ANY value of M will give us a line that moves through the Origin. Try graphing any of the following lines and you'll see:
Y = X
Y= 2X
Y = 100X
Y = (-1)X
Y = (-99)X
Y = .00005X
etc.
GMAT assassins aren't born, they're made,
Rich
When a line is written in slope-intercept 'format' (Y = MX + B) if there is NO "B" value, then the line moves through the Origin (re: the point 0,0). The slope (re: the "M") has no impact on that, meaning that as long as B=0, then ANY value of M will give us a line that moves through the Origin. Try graphing any of the following lines and you'll see:
Y = X
Y= 2X
Y = 100X
Y = (-1)X
Y = (-99)X
Y = .00005X
etc.
GMAT assassins aren't born, they're made,
Rich
