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In how many ways can 5 identical blue marbles and 6 identical green marbles be arranged in a row such that all the blue marbles are grouped together?
A. 120 B. 30 C. 24 D. 11 E. 7
Consider all 5 blue marbles as a single unit: {bbbbb}. Along with the 6 green marbles, we have a total of 7 units: {bbbbb}, {g}, {g}, {g}, {g}, {g}, {g}. The number of arrangements for these 7 units will be 7!/6! = 7.
In how many ways 5 identical blue marbles and 6 identical green marbles can be arranged in a row, so that all the blue marbles are together?
A. 120 B. 30 C. 24 D. 11 E. 7
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Think of the 5 identical blue marbles as one unit, so it gives us 1+6 = 7 units, these can be arranged in 7! ways BUT we have 6 identical units in these 7 units. We know that in combinatorics we have to divide by the number of identical units so the answer = 7!/6!= 7