Official Solution:Alice has $15, which is enough to buy 11 muffins and 7 brownies. Is $45 enough to buy 27 muffins and 27 brownies? This is a 700+ level question.
Given: \(11m+7b \le 15\), where \(m\) and \(b\) are the prices of one muffin and one brownie, respectively.
Question: Is \(27m+27b \le 45\)? Reduce by 3: \(9m+9b \le 15\). The question essentially asks whether we can substitute 2 muffins with 2 brownies.
If \(m \gt b\), we can easily substitute 2 muffins with 2 brownies (since \(2m\) will be more than \(2b\)). But if \(m \lt b\), we won't know this for sure.
However, consider the case when we are told that we can substitute 3 muffins with 3 brownies. In both cases (\(m \gt b\) or \(m \lt b\)), it would mean that we can substitute 2 (fewer than 3) muffins with 2 brownies, but again we won't be sure whether we can substitute 4 (more than 3) muffins with 4 brownies.
(1) $15 is enough to buy 7 muffins and 11 brownies.
\(7m+11b \le 15\): We can substitute 4 muffins with 4 brownies, so according to the above, we can certainly substitute 2 muffins with 2 brownies. Sufficient.
(1) $15 is enough to buy 10 muffins and 8 brownies.
\(10m+8b \le 15\): We can substitute 1 muffin with 1 brownie, so according to the above, this does not ensure that we can substitute 2 muffins with 2 brownies. Not sufficient.
Answer: A