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mikemcgarry
Let S be the set of all positive integers that, when divided by 8, have a remainder of 5. What is the 76th number in this set?
(A) 605
(B) 608
(C) 613
(D) 616
(E) 621

The first number in the set is 5, since 5/8 = 0 remainder 5.

The second number in the set is 5 + 1(8).

The third number in the set is 5 + 2(8).

The fourth number in the set is 5 + 3(8).

Continuing the pattern established, we see that the 76th number in the set is 5 + 75(8) = 605.

Answer: A
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Since the use of mathematical terminology here might be confusing for some people, I'll point out that sets are, by definition, not in any order at all. It doesn't mean anything to talk about the "first element" or the "76th number" in a set; the set {a, b, c} is identical to the set {c, b, a}. An ordered list of values is a sequence, not a set.
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mikemcgarry
Let S be the set of all positive integers that, when divided by 8, have a remainder of 5. What is the 76th number in this set?
(A) 605
(B) 608
(C) 613
(D) 616
(E) 621


For a set of practice problems on sequences, as well as the OE for this problem, see:
https://magoosh.com/gmat/2014/gmat-prac ... sequences/

Mike :-)

Series will begin from 5,13,21

a_76 = a + (n-1) d
= 5 + 75 * 8
= 5+ 560 + 40
= 605

A
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since remainder is 5 when divided by 8, the first num needs to be 5 itself.

now remainder is 5 that means each num after 5 will be 8 higher than preceding num.

so our sequence will be = 5,13,21,29,...

we need to find 76th num in sequence.

we can easily use the formula of an = a1 + (n-1)d

here d= 8 (13-5)
a1= 5
n = 76

a76 = 5 + (76-1) *8

a76 = 605

choice A

mikemcgarry
Let S be the set of all positive integers that, when divided by 8, have a remainder of 5. What is the 76th number in this set?
(A) 605
(B) 608
(C) 613
(D) 616
(E) 621


For a set of practice problems on sequences, as well as the OE for this problem, see:
https://magoosh.com/gmat/2014/gmat-prac ... sequences/

Mike :-)
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