Bunuel
Tough and Tricky questions: Geometry.
Does the area of a certain square greater than the area of a certain rectangle?
(1) One side of the rectangle equals to the side of the square.
(2) One side of the rectangle is twice greater than the side of the square.
Kudos for a correct solution. OFFICIAL SOLUTION:(C) The area of a square is a², where a is the side of a square. The area of a rectangle is bc, where b and c are the sides of a rectangle.
Statement (1) tells us that the figures have one equal side. Clearly, that is not enough. If the smaller side of the rectangle is equal to the side of the square, then the area of the rectangle is greater. If the bigger side of the rectangle is equal to the side of the square, then the area of the square is greater. If the rectangle is a square as well, then their areas equal. Therefore statement (1) by itself is NOT sufficient.
Statement (2) tells us that one side of the rectangle is twice greater than the side of the square. If the other side of the rectangle is greater as well, then the area of the rectangle is greater. However if the other side of the rectangle is less than half the side of the square, then the area of the square is greater. Statement (2) by itself is NOT sufficient.
If we use the both statements together the area of the rectangle is greater, because in this case the sides of the rectangle must be a and 2a. So the area of the rectangle is 4a². The correct answer is C.