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Bunuel
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Bunuel

Tough and Tricky questions: Geometry.



Does the area of a certain square greater than the area of a certain rectangle?

(1) One side of the rectangle equals to the side of the square.

(2) One side of the rectangle is twice greater than the side of the square.

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We need to remember all sides of a square are the same - and their area is
For a rectangle's area to be bigger than that of the square we just need to one side of the rectangle to be bigger while the other side remains the same OR we need one side of the rectangle be a square of the sides of the square.

A) Insufficient because if one side is equal to the rectangle, we have no info on the rectangle's other side which could be bigger or smaller

B) Insuff Because we have no info on other side of rect - it could be as small as 1.

C is correct. If we know one side of Rectangle is equal to squre and the other side is bigger, then area's can be compared
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Bunuel

Tough and Tricky questions: Geometry.



Does the area of a certain square greater than the area of a certain rectangle?

(1) One side of the rectangle equals to the side of the square.

(2) One side of the rectangle is twice greater than the side of the square.

Kudos for a correct solution.

OFFICIAL SOLUTION:

(C) The area of a square is a², where a is the side of a square. The area of a rectangle is bc, where b and c are the sides of a rectangle.

Statement (1) tells us that the figures have one equal side. Clearly, that is not enough. If the smaller side of the rectangle is equal to the side of the square, then the area of the rectangle is greater. If the bigger side of the rectangle is equal to the side of the square, then the area of the square is greater. If the rectangle is a square as well, then their areas equal. Therefore statement (1) by itself is NOT sufficient.

Statement (2) tells us that one side of the rectangle is twice greater than the side of the square. If the other side of the rectangle is greater as well, then the area of the rectangle is greater. However if the other side of the rectangle is less than half the side of the square, then the area of the square is greater. Statement (2) by itself is NOT sufficient.

If we use the both statements together the area of the rectangle is greater, because in this case the sides of the rectangle must be a and 2a. So the area of the rectangle is 4a². The correct answer is C.
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(1) All squares are rectangles.

The rectangle may be a congruent square, in which case the areas are equal.

The rectangle may also be non-square, in which case we need the other dimension (length or width) to meet sufficiency.

Strike A/D.

(2) We again only know one dimension. NOT sufficient.

Strike B.

(1/2) We know know the relative dimensions for both length and width of each of the two rectangles. Sufficient.

The answer is C.
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