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25 Feb 2015, 03:26
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A
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Difficulty:
95%
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Question Stats:
41% (01:49) correct
59%
(01:44)
wrong
based on 549
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If x is an odd negative integer and y is an even integer, which of the following statements must be true?
I. (3x - 2y) is odd
II. xy^2 is an even negative integer
III. (y^2 - x) is an odd negative integer
A. I only
B. II only
C. I and II
D. I and III
E. II and III
Kudos for a correct solution.
I. (3x - 2y) is odd
II. xy^2 is an even negative integer
III. (y^2 - x) is an odd negative integer
A. I only
B. II only
C. I and II
D. I and III
E. II and III
Kudos for a correct solution.
Plastelin
Joined: 19 Jan 2014
Last visit: 03 Sep 2018
Posts: 23
Given Kudos: 1
Schools: Duke '17 (M) Darden '17 (A$) Sloan '17 (D)
GMAT 1: 730 Q50 V39
WE:Accounting (Accounting)
25 Feb 2015, 05:30
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If x is an odd negative integer and y is an even integer, which of the following statements must be true?
I. (3x - 2y) is odd
3x - is always negative and odd
2y - can be 0, when y=0, or always even integer (positivie or negative)
odd integer +/- even integer = always odd
I statement is always true
II. xy^2 is an even negative integer
y can be 0 => xy^2 = 0 (non-negative even) => II statement is not true
III. (y^2 - x) is an odd negative integer
y can be 0 => -x will be positive => III statement is not true
basing on above, only I statement will always be true
answer is A
I. (3x - 2y) is odd
3x - is always negative and odd
2y - can be 0, when y=0, or always even integer (positivie or negative)
odd integer +/- even integer = always odd
I statement is always true
II. xy^2 is an even negative integer
y can be 0 => xy^2 = 0 (non-negative even) => II statement is not true
III. (y^2 - x) is an odd negative integer
y can be 0 => -x will be positive => III statement is not true
basing on above, only I statement will always be true
answer is A
General Discussion
28 Feb 2015, 06:55
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Bunuel
Let x = -1, y = 2
Option I: (3x - 2y) = 3(-1) - 2(2) = -7 is ODD
Option II: xy^2 = (-1)(2^2) = -4 is EVEN NEGATIVE
Option III. (y^2 - x) = 2^2 - (-1) = 5 is ODD POSITIVE
Since the question involves Even and Odd numbers, let us also consider y = 0.
Option I: (3x - 2y) = 3(-1) - 2(0) = -3 is ODD
Option II: xy^2 = (-1)(0^2) = 0 is EVEN POSITIVE
Option III. This condition was proved false using the above values.
Hence only condition I is satisfied.
Hence option A.
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