In the figure above, the point on segment JK that is four times as far

Question

cgpq_img1.png In the figure above, the point on segment JK that is four times as far from K as it is from J is: A. (-1, 3) B. (-1/3, 7/3) C. (0, 2) D. (4/3, 1/3) E. (2, 0)

aniteshgmat1101 · Answer

Answer is A.
The point will be 1 unit(m) far from J and 3 units(n) from K. So, by the ratio-formula, point = (m * j1 + n * k1)/m+n , (m * j2 + n * k2)/m+n.
So, the correct option is A.

iamdp · Answer

hi

Plz see the attached pic

Sridutt · Answer

The Q says the point is 4 times from K and one time from J.
Split line into 5 parts (1+4).

Taking a cue that the line passes diagonally through 5 squares, the first diagonal point from J must be the POI(-1,3).

mvictor · Answer

right from the start we can eliminate C, D, E
the point lies in the II quadrant
we can see that the slope is y=-x
plug in coordinates of B, and we can see that   /  
 / 
we get
(5/3)/(-7/3), or -(5/7)
which is not what we are looking for.
the only choice we have is A

lipsi18 · Answer

The required point is far from F =a, therefore from K=4a;total length is 5a; therefore point will be on 2nd quadrant and only option A satisfies. and it is a distance away from J and 4a distance away from K; 
Therefore answer is A (-1,3)
 
Thanks

RaOwl · Answer

Length of segment jk= x + 4x = 5x
On horizontal x axis--
5x corresponds to distance between points -2 & 3 ie 5 units 
Hence x= 1 -- this gives us the horizontal distance of this point from J 
Similarly 5x corresponds to distance between y coordinates 4 & -1
Hence x = 1 gives the vertical distance of this point from J .
Hence the point has coordinates of ( -2+1, 4-1)---- ( -1,3)

Please gives kudos if you like the solution.

Bunuel · Answer

MAGOOSH OFFICIAL SOLUTION:

Call the point P. Then, PK = 4*JP. Of course, JP + PK = JK, so JP + 4*JP = 5*JP = JK, and JP = (1/5)*JK. Point P should be one fifth of the segment away from J. This would be the point (–1, 3).

Answer = (A)

EMPOWERgmatRichC · Answer

Hi All,

The 'design' of this prompt includes some patterns that you can take advantage of to avoid having to do a lot of 'math work.' To start, the answer choices are all specific co-ordinates, so you can use them against the question and 'work visually.' Second, we're asked for a point that is "4 TIMES as far from K as it is from J", so we're clearly looking for an answer that is really 'close' to Point J. Third, the line can be 'broken down' into 5 equal-length diagonal segments; this is REALLY helpful since we can then find the point that is 4 "units" from K and 1 "unit" from J....

Final Answer:  A

GMAT assassins aren't born, they're made,
Rich

nissstheone · Answer

can this be solved from ratio method as well ? If yes, can someone post it ?

bumpbot · Answer

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In the figure above, the point on segment JK that is four times as far

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In the figure above, the point on segment JK that is four times as far

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