Bunuel
At Didymus Corporation, there are just two classes of employees: silver and gold. The average salary of gold employees is $56,000 higher than that of silver employees. If there are 120 silver employees and 160 gold employees, then the average salary for the company is how much higher than the average salary for the silver employees?
A. $24,000
B. $28,000
C. $32,000
D. $36,000
E. $40,000
Kudos for a correct solution. MAGOOSH OFFICIAL SOLUTION:Method I: using sumsWe can use this if we pick a value for the average salary for the silver employees. It actually doesn’t matter what value we pick, because averages will fall in the same relative places regardless of whether all the individual values are slid up and down the number line. The easiest value by far to pick is zero. Let’s pretend that the silver folks make $0, and the gold folks make $56. (I divided dollars by 1000 for simplicity).
Now, we also have to simplify the numbers of employees. We could reduce the number of employees as long as we preserve the relative ratio.
silver : gold = 120:160 = 12:16 = 3:4
So everything would be the same if we just had 3 silver employees and 4 gold employees. OK, now find the sums.
silver = 3*0 = 0
gold = 4*56
I am not even going to bother to multiply that out, because we know that the next step is to divide by 7, the total number of employees.
total average = 4*56/7 = 4*8 = 32
The average salary is $32,000, which is $32,000 higher than the average for the silver employees. Answer = (C)
Method II: proportional placement of the total averageThe ratio of silver employees to gold employees is
silver : gold = 120:160 = 12:16 = 3:4
If we divide the distance between the two averages by 7, then silver will be “four parts” away from the total average, and gold will be “three parts” away.
Well, the difference is $56,000, so that divided by 7 is $8000. That’s one part. Four parts would be $32,000, which has to be the distance from the silver average to the total average.
Answer = (C)