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07 Nov 2015, 09:54
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
53% (01:59) correct
47%
(02:11)
wrong
based on 536
sessions
History
Date
Time
Result
Not Attempted Yet
Jamboree and GMAT Club Contest Starts
QUESTION #1:
X Y
+Y X
________
The sum of the two digit numbers above is a three digit number PQ5, where each letter X, Y, P, and Q represents a different non zero digit. Which of the following can be the value of X?
I) 7
II) 8
III) 9
(A) I only
(B) II only
(C) III only
(D) I and II only
(E) I , II and III
Check conditions below:
For the following two weekends we'll be publishing 4 FRESH math questions and 4 FRESH verbal questions per weekend.
To participate, you will have to reply with your best answer/solution to the new questions that will be posted on Saturday and Sunday at 9 AM Pacific.
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There is only one Grand prize and student can choose out of the above mentioned too options as per the conditions mentioned in blue font.
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GMAT Club reserves the rights to modify the terms of this offer at any time.
To participate, you will have to reply with your best answer/solution to the new questions that will be posted on Saturday and Sunday at 9 AM Pacific.
Then a week later, respective forum moderators will be selecting 2 winners who provided most correct answers to the questions, along with best solutions. Those winners will get 6-months access to GMAT Club Tests.
PLUS! Based on the answers and solutions for all the questions published during the project ONE user will be awarded with ONE Grand prize. He/She can opt for one of the following as a Grand Prize. It will be a choice for the winner:
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Bookmark this post to come back to this discussion for the question links - there will be 2 on Saturday and 2 on Sunday!
There is only one Grand prize and student can choose out of the above mentioned too options as per the conditions mentioned in blue font.
All announcements and winnings are final and no whining
GMAT Club reserves the rights to modify the terms of this offer at any time. NOTE: Test Prep Experts and Tutors are asked not to participate. We would like to have the members maximize their learning and problem solving process.
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07 Nov 2015, 10:17
Kudos
Bookmarks
Digit P has to be 1 as we are adding 2 two digit numbers
Y+X=15
XY= 78 or 87
YX= 87 or 78
So X can be either 7 or 8
If X=9 , then
69
+96
165
In this case Q will be 6 . So the digits won't be distinct.
Answer D
Y+X=15
XY= 78 or 87
YX= 87 or 78
So X can be either 7 or 8
If X=9 , then
69
+96
165
In this case Q will be 6 . So the digits won't be distinct.
Answer D
07 Nov 2015, 10:27
Kudos
Bookmarks
ok, so we have
XY+
YX
= PQ5, where all the digits are distinct.
from this, we can conclude that X+Y is equal to either a 1 digit number or a 2 digit number, the units digit of which would be 5.
from the given possibilities:
I x = 7, then we must have Y equal to 8 so that the units digit would be 5.
78+87 = 165 - since all the digits are distinctive, then yes, X can be 7.
II x = 8, this works the same way as I. if x =8 then y = 7, and we get 87+78 = 165. again, this satisfies the conditions.
If we stumble and don't know what to do next, we can just eliminate A, B, and C, and try to make a smart guess with a chance of getting the right answer 1/2.
III x = 9, let's see, if X =9, then Y must be 6.
96+69 = 165. Same thing as I and II right? no! it is not. The condition is that X, Y, P, and Q are distinct digits, which mean that no digit should be repeated. In this case we have Q has the same digit as Y. This does not satisfy the condition, and thus, the answer is D.
XY+
YX
= PQ5, where all the digits are distinct.
from this, we can conclude that X+Y is equal to either a 1 digit number or a 2 digit number, the units digit of which would be 5.
from the given possibilities:
I x = 7, then we must have Y equal to 8 so that the units digit would be 5.
78+87 = 165 - since all the digits are distinctive, then yes, X can be 7.
II x = 8, this works the same way as I. if x =8 then y = 7, and we get 87+78 = 165. again, this satisfies the conditions.
If we stumble and don't know what to do next, we can just eliminate A, B, and C, and try to make a smart guess with a chance of getting the right answer 1/2.
III x = 9, let's see, if X =9, then Y must be 6.
96+69 = 165. Same thing as I and II right? no! it is not. The condition is that X, Y, P, and Q are distinct digits, which mean that no digit should be repeated. In this case we have Q has the same digit as Y. This does not satisfy the condition, and thus, the answer is D.
