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Bunuel
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(5!*4! + 6!*5!)/31
=5!(4! + 6!)/31
=120 ( 24 + 720)/31
=(120 * 744)/31
= 120 * 24

Units digit of the above product will be equal to 0

Answer E
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Hi

Any factorial above 4 will have 0 as a units digit. Therefore, it's a units digit of 0 divided by another units digit rendering a 0 as the outcome's units digit.
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I say (E) as well.

The numerator adds up to zero (the units digit of 5! and 6! is zero) so the answer can only be zero.

PS: Always appreciate questions that you can solve by using logic rather than doing a lot of math! lol
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Great Question.
Here is what i did in this one -->
(5!*4! + 6!*5!)/31 => 5!*4!(31)/31 => 5!*4!
Hence it will always end with a zero due to the presence of a 2 and a 5.

Hence E.
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Harshit401
E

Sent from my Lenovo A6020a46 using GMAT Club Forum mobile app
2880×31=89280
86400+2880=89280
6!*5!=86400
5!*4!=2880

Sent from my Lenovo A6020a46 using GMAT Club Forum mobile app
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(5!*4! + 6!*5!)/31

=5!*4!(1+6*5)/31

= 5!*4!(31)/31

=5!*4!

5! always contains a 10 i.e 5*2 (apart from 1*3*4)
and any whole number multiplied by 10 will give out 0 in its units digit

So 0 will be the answer :)

Bunuel
What is the units digit of \(\frac{(5!*4! + 6!*5!)}{31}\)?

A. 4
B. 3
C. 2
D. 1
E. 0
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