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Bunuel
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Bunuel
If a, b, c, d, and x are nonzero numbers, which of the following conditions must be true for \((ax)^{61}(bx)^{21}(cx)^{14}(dx)^6 > 0\)?

A. x > 0
B. a × b > 0
C. c × d > 0
D. a × d > 0
E. a × b < 0

To start, we can ignore any bases with even exponents because those quantities are positive. So we are left with:

a^61 * x^61 * b^21 * x^21 > 0

a^61 * b^21 * x^42 > 0

Dividing the inequality by a^60 * b^20 * x^42 (notice that this is a positive quantity), we have:

a * b > 0

Answer: B
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Bunuel
If a, b, c, d, and x are nonzero numbers, which of the following conditions must be true for \((ax)^{61}(bx)^{21}(cx)^{14}(dx)^6 > 0\)?

A. x > 0
B. a × b > 0
C. c × d > 0
D. a × d > 0
E. a × b < 0

Given \((ax)^{61}(bx)^{21}(cx)^{14}(dx)^6 > 0\)

Since even power will always result in positive, irrespective of the sign of the base & odd power is dependent on the sign of the base.

We get, (+ve) * (+ve) * (+ve) * (+ve) > 0

or

(-ve) * (-ve) * (+ve) * (+ve) > 0

Now if ax > 0 & bx > 0, then it means a, x & b > 0 or a, x & b < 0

if ax < 0 & bx < 0, then it means a & b > 0 & x < 0 or a & b < 0 & x > 0

we can see that

a * b > 0 for any a, x & b combination.

Answer B.


Thanks,
GyM
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a*b should be more than 0 as they have odd powers.
rest c and d have even powers so they will always be positive
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This was super helpful. Thank you, Jeff!
JeffTargetTestPrep
Bunuel
If a, b, c, d, and x are nonzero numbers, which of the following conditions must be true for \((ax)^{61}(bx)^{21}(cx)^{14}(dx)^6 > 0\)?

A. x > 0
B. a × b > 0
C. c × d > 0
D. a × d > 0
E. a × b < 0

To start, we can ignore any bases with even exponents because those quantities are positive. So we are left with:

a^61 * x^61 * b^21 * x^21 > 0

a^61 * b^21 * x^42 > 0

Dividing the inequality by a^60 * b^20 * x^42 (notice that this is a positive quantity), we have:

a * b > 0

Answer: B
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