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12 May 2016, 04:52
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
71% (02:41) correct
29%
(02:08)
wrong
based on 62
sessions
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A spherical sphere of radius 4 cm is divided into eight equal parts by cutting it in halves along the same axis as given in the attached image. Find the surface area of each of the final piece.
A.20π
B.25π
C.24π
D.19π
E.18π
A.20π
B.25π
C.24π
D.19π
E.18π
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geometry.jpg [ 16.2 KiB | Viewed 17170 times ]
12 May 2016, 06:15
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1/8 th of a sphere can be imagined to have 3 different faces , two of which are semi-circles and the 3rd one to be the 1/8th of the outer surface of a sphere
So, the area of our outer surface of the sphere = 1/8 x 4 x pi x r^2 = 1/8 x 4 x pi x 4^2 = 8 x pi
Now, the area of the inner surfaces = 2 x Area of semi-circle = 2 x 1/2 x pi x r^2 = 16 x pi
Total area = 8 pi + 16 pi = 24 pi
answer : C
So, the area of our outer surface of the sphere = 1/8 x 4 x pi x r^2 = 1/8 x 4 x pi x 4^2 = 8 x pi
Now, the area of the inner surfaces = 2 x Area of semi-circle = 2 x 1/2 x pi x r^2 = 16 x pi
Total area = 8 pi + 16 pi = 24 pi
answer : C
07 Jun 2019, 05:13
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hi, can anyone please explain the solution?
