There are 100 apples in a bag of which 98% are green and the rest red.

Question

There are 100 apples in a bag of which 98% are green and the rest red. How many green apples do you need
to remove so that only 96% of the apples are green?

A. 40
B. 8
C. 15
D. 25
E. 50

Abhishek009 · Accepted Answer

\frac{98 - x}{100 - x} = \frac{96}{100}

Or,  9800 - 100x = 9600 - 96x

Or,  200 = 4x

Or,  x = 50 
  
Hence, only 50 green apples need to be removed from the bag , answer will be (E)

BrentGMATPrepNow · Answer

There are 100 apples in a bag of which 98% are green and the rest red.  
So, we can conclude that (initially) there are  98 green  apples and  2 red  apples in the bag.

If (after we remove some green apples) 96% of the apples are green. This means that 4% of the apples are red. 
So, let's reword the question as "How many green apples do you need to remove so that  4%  of the apples are red?"

We already know there are  2 red  apples, and we know that  2 /50 =  4% 
That is, if there were 50 apples altogether, and  2  were red, then 4% of the apples would be red. 
In order to get 50 apples altogether, we must remove 50 apples from the bag.

Answer:  E

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gracie · Answer

let a=total apples remaining after green apples removed
.04a=2 red apples
a=50 total apples
50-2=48 green apples remaining
98-48=50 green apples removed

Mehemmed · Answer

98-x=(100-x)*96/100

Solving this equation,we get x-24x/25=2,hence x=50

ScottTargetTestPrep · Answer

We see that there are 98 green apples and 2 red apples. We can let n = the number of green apples to remove and create the equation:

(98 - n)/(100 - n) = 96/100

100(98 - n) = 96(100 - n)

9800 - 100n = 9600 - 96n

200 = 4n

50 = n

Answer: E

mohd_int · Answer

\frac{x}{(x+2)} =  \frac{96}{100}

100x=96x+192

4x=192

x= \frac{192}{4}

x=48 not the answer

the number of green apple that should be removed is 98-48 =  50

chandra004 · Answer

96(100-x)/100 = 100 - x - 2 .....{x is the total no. of green apples required to remove and 2 is the count of red apples}
Hence x = 50.
E is the answer

mimajit · Answer

This is how i solved.
Total green aplles = 98 and Red aplles = 2 Total apples = 100
TArget question = how many apples to remove to get 96% apples Green.

We know that there are 2 apples which are red. They need to be 4 % of the total no of apples 
4/100* X = 2 
Sloving for X we get 50

Which means if there are 50 apples in total 2 red apples mean 4% and remainig 48 apples = green = 96 %

We know total green apples = 98 . How many should i remove to reach 48 apples = 98-50 = 48 apples green apples
= 50 = E

S1937 · Answer

ScottTargetTestPrep , your equation means that if we remove 50 apples from 98apples, the result{48apples} is 96% of 100. This question doesnt make any sense to me. Pls is something wrong with this question or wrong with my concept of math? Does GMAC actualy set this sort of question that doesnt make real proportionate sense?

S1937 · Answer

Thanks Brent but is there a typo in this question or is it total of 100 apples really? Cos it doesnt make sense to me at all

dave13 · Answer

hey pushpitkc , niks18

is my approach correct ? We have 98 green and 2 red apples. 98-x = 0.96(100-x) 98-x = 96-0.96x 98-96 = x-0.96x 2 = 0.04x x = 50

pushpitkc · Answer

Your approach is bang on dave13 - btw, what is x??

(Just kidding!!)

Kimberly77 · Answer

GMATinsight , could we solve this question with your usual cross ratio method or could you share your insight on this question please? Thanks a bunch.

natacini · Answer

The point is that we cannot add Red Apples, than we need to remove green.

There are 100 apples in a bag of which 98% are green and the rest red.

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There are 100 apples in a bag of which 98% are green and the rest red.

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