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At a certain soccer club, the number of players increased by 10 percent between 2015 and 2016. If the number of male players decreased by 5 percent and the number of female players increased by 15 percent, what is the ratio of female players to male players in 2015? A) 1:3 B) 1:2 C) 3:2 D) 2:1 E) 3:1
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let no. male players be x and female players be y as per the question stem : x*95/100+y*115/100 = (x+y)*110/100 => y/x =3/1 -> option E
Isnt this the ratio of 2015 not 2016?
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Even the increase no. would drift with the same ratio cause we are considering an overall increase in the same exact proportion. We can't ascertain a ratio with the conditional part of a question stem and it was mentioned only to manipulate it further. Assume total to be 100; let x and y part be 30 and 70. Now, an overall increase of 10% will also let x and y part to go up by 3 and 7 respectively and not to mention that the ratio doesn't change.
At a certain soccer club, the number of players increased by 10 percent between 2015 and 2016. If the number of male players decreased by 5 percent and the number of female players increased by 15 percent, what is the ratio of female players to male players in 2015? A) 1:3 B) 1:2 C) 3:2 D) 2:1 E) 3:1
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Edited the question. It asks about the ration in 2015.
Veritas Prep Official Solution:
We can solve this one with the weighted average mapping strategy or with algebra. For the mapping strategy:
-5%...............10%......15%
M..........15...........5......F
This gives us a female:male ratio of 15:5, or 3:1.
To solve algebraically, we can set up the following equation: \(1.1(f+m)=1.15f+.95m\). By manipulating, we can get to \(0.15m =0.05f\), or \(\frac{f}{m}=\frac{0.15}{0.05}=\frac{3}{1}\).
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.