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This question is really confusing, it states that Team A chooses a line up of M-F-M-F-M-F and then says this line up is one of how many different possible lineups.. Doesn't that mean that this is technically 1 of 6! line ups? I'm confused, any help will be appreciated!!
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Sanaya24
This question is really confusing, it states that Team A chooses a line up of M-F-M-F-M-F and then says this line up is one of how many different possible lineups.. Doesn't that mean that this is technically 1 of 6! line ups? I'm confused, any help will be appreciated!!

It seems you did not read the question and provided solutions carefully. The lineup is fixed as M-F-M-F-M-F. However, the men and women themselves, in their respective places, can be arranged in different ways: 3! ways for the men and 3! for the women. This results in a total of 3!*3! = 36 specific lineups.
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­Draw slots and fill in your options like any permutation:

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For anyone who has the doubt, why 720 cannot be the answer, I have spent quiet some time decoding that too. So according to my understanding, if you're someone who is selecting 6! or 720 as the answer you might be interpreting that the question is asking the total number of arrangements of lining up 3 males and 3 females. But imagine this
720 would include cases where mmfmff or mmmfff or mfmffm etc. are also possible, which is 6!/3!*3! = 20 , so for every 20 line ups there will be 36 ways (3!*3!) ways in which the males and females will be arranged.

So either it was interpreted as mfmfmf out of 20 different combinations or 36 ways of arranging mfmfmf.
20 is anyway to part of the answer choices.
Hence Ans D.­
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This question is very confusing and its because its hard to determine what the question means by the term "lineups" at the end of the last sentence. Is "lineups" referring to all the different ways that the specific MALES and FEMALES can be arranged in the predetermined MFMFMF set up, or does "lineups" mean all the possible ways to arrange the genders, as in MMMFFF, MFMMFF, etc. It doesn't explicitly say which "lineups" its referring to.

"The lineup that Team A chooses will be one of how many different possible lineups" could just as easily mean TEAM A chose MFMFMF out of all the possible lineups that the genders could have been arranged. They chose MFMFMF out of MMFFMF, MMMFFF, FFFMMM, etc. and how many of those COULD they have chosen?

OR

It could mean that TEAM A already chose MFMFMF as their predetermined set up and the question wants to know how many different arrangements you can put the specific males and females in that specific "lineup".

IMO the language isn't clear.
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Hey Bunuel,

A small clarification is required please - In GMAT, how do we infer whether the objects provided in the question stem are identical or not. For ex- in here, it could have been the case that all 3 Males are identical & 3 Females are identical.
Does this mean, the question will explicitly state that Males are identical and so on?
I face this constraint confusion always whenever objects are involved which may or may not be identical. Since we only divide when there is an identical number of objects. If 3 males and 3 females were identical, we would have divided by 3!3!.
Please guide me here.
Thanks a ton :)
Bunuel
Raihanuddin

Hi Bunuel,

Could you please clarify me the following? the

I was also confused by the wording. But I was sure that it won't be 6! ways because MMMFFF can't be arranged in 6! ways.

I thought it would be 6!/(3!*3!) = 20

But this option is not given. So, I had to figure out the solution by doing 3!*3! = 36

Now, I am not sure what the difference is between 6!/(3!*3!) = 20 and 3!*3! = 36.

I think 6!/(3!*3!) = 20 means the number of the different possible combination. and

3!*3! = 36 means the arrangement with a certain condition.

Please clarify the confusion.

3!*3! is the number of permutations when the lineup is male, female, male, female, male, female (M-F-M-F-M-F) only.

6!/(3!3!) is the number of permutations of 3 males and 3 females without any restrictions.
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saransh2797
Hey Bunuel,

A small clarification is required please - In GMAT, how do we infer whether the objects provided in the question stem are identical or not. For ex- in here, it could have been the case that all 3 Males are identical & 3 Females are identical.
Does this mean, the question will explicitly state that Males are identical and so on?
I face this constraint confusion always whenever objects are involved which may or may not be identical. Since we only divide when there is an identical number of objects. If 3 males and 3 females were identical, we would have divided by 3!3!.
Please guide me here.
Thanks a ton :)
Bunuel
Raihanuddin

Hi Bunuel,

Could you please clarify me the following? the

I was also confused by the wording. But I was sure that it won't be 6! ways because MMMFFF can't be arranged in 6! ways.

I thought it would be 6!/(3!*3!) = 20

But this option is not given. So, I had to figure out the solution by doing 3!*3! = 36

Now, I am not sure what the difference is between 6!/(3!*3!) = 20 and 3!*3! = 36.

I think 6!/(3!*3!) = 20 means the number of the different possible combination. and

3!*3! = 36 means the arrangement with a certain condition.

Please clarify the confusion.

3!*3! is the number of permutations when the lineup is male, female, male, female, male, female (M-F-M-F-M-F) only.

6!/(3!3!) is the number of permutations of 3 males and 3 females without any restrictions.

Where clarification is necessary, it will be given. If it's not explicitly stated and the context doesn’t make it clear, use common sense: people are distinct, so their individual positioning changes the lineup, meaning order matters.
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ganand
Team A and Team B are competing against each other in a game of tug-of-war. Team A, consisting of 3 males and 3 females, decides to lineup male, female, male, female, male, female. The lineup that Team A chooses will be one of how many different possible lineups?

(A) 9
(B) 12
(C) 15
(D) 36
(E) 720
The question is relatively easy, could be solved in 10 seconds , use fill in the blanks methods,,,, MFMFMF,,,,, so 3 gaps of M, 3 of F,,,,3*3*2*2*1*1=36 ways simple
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ganand
Team A and Team B are competing against each other in a game of tug-of-war. Team A, consisting of 3 males and 3 females, decides to lineup male, female, male, female, male, female. The lineup that Team A chooses will be one of how many different possible lineups?

(A) 9
(B) 12
(C) 15
(D) 36
(E) 720
To determine the number of possible lineups for Team A, where 3 males (M) and 3 females (F) are arranged in an alternating pattern (M, F, M, F, M, F), we can follow these steps:
  1. Arrange the Males: The 3 males can be arranged in the 3 male positions in 3!3!3! (3 factorial) ways. Calculating 3!3!3!:
    3!=3×2×1=63! = 3 \times 2 \times 1 = 63!=3×2×1=6
  2. Arrange the Females: Similarly, the 3 females can be arranged in the 3 female positions in 3!3!3! ways. Calculating 3!3!3!:
    3!=3×2×1=63! = 3 \times 2 \times 1 = 63!=3×2×1=6
  3. Total Arrangements: Since the arrangements of males and females are independent, the total number of lineups is the product of the two arrangements:
    3!×3!=6×6=363! \times 3! = 6 \times 6 = 363!×3!=6×6=36
Therefore, the total number of different possible lineups for Team A is 36.
Answer: (D) 36
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This Question is very confusing. One could find a difference between
"how many different possible lineups?" and "how many different possible lineups from the given lineup?"

Can one tell if this is an actual gmat question please?
ganand
Team A and Team B are competing against each other in a game of tug-of-war. Team A, consisting of 3 males and 3 females, decides to lineup male, female, male, female, male, female. The lineup that Team A chooses will be one of how many different possible lineups?

(A) 9
(B) 12
(C) 15
(D) 36
(E) 720
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tryorcry
This Question is very confusing. One could find a difference between
"how many different possible lineups?" and "how many different possible lineups from the given lineup?"

Can one tell if this is an actual gmat question please?


Yes, this is an official GMAT question:



Please review the discussion. This question has already been discussed in quite a bit of detail in the thread.
Attachment:
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I understand this is an official question but I still have my doubts.
It says one of how many possible lineups and calls the aforementioned lineup as "one".
So one of how many total could mean how many such blueprints possible? Or how many kinds of lineups possible with one being M,F,M,F,M,F?
In that case shouldn't it be 6!/3!*3! = 20? Kindly help me out.

PS:- Yes I read the thread as well but I am not satisfied.
Let me try rephrasing it again:
" The lineup that Team A chooses will be one of how many different possible lineups?"
This in other words IMO says, the lineup that team A chooses = M,F,M,F,M,F is one out of how many different "possible" lineups.
It calls that setup a "lineup" so the number of lineups must technically be the numbers of ways of having an M,F combo arranged in different ways right?
If it were like how the answer is, it should be like how many different possible arrangement of the lineup are there, or something like that?
Quote:


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I was also confused by the wording. But I was sure that it won't be 6! ways because MMMFFF can't be arranged in 6! ways considering we only want to determine the lineup (sequence of Males and females).

I thought it would be 6!/(3!*3!) = 20

But this option is not given.

After reading the discussion, my understanding is :-
The question stem- The lineup that Team A chooses will be one of how many different *possible lineups*? Question is asking different ways of arranging people in the chosen lineup (MFMFMF).
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ganand
Team A and Team B are competing against each other in a game of tug-of-war. Team A, consisting of 3 males and 3 females, decides to lineup male, female, male, female, male, female. The lineup that Team A chooses will be one of how many different possible lineups?

(A) 9
(B) 12
(C) 15
(D) 36
(E) 720
For anyone still struggling with the wording or trying to visualise this question, solving it slot-by-slot using the Fundamental Counting Principle (FCP) makes the constraint crystal clear.
The prompt states the team decides to line up in this exact pattern: M - F - M - F - M - F. This fixes the gender roles for all 6 spots.
Let's assume our 3 unique males are (\(M_1, M_2, M_3\)) and 3 unique females are (\(F_1, F_2, F_3\)). Now, let's fill the slots one by one from left to right:
  • Slot 1 (Must be Male): We have 3 choices available (\(M_1, M_2,\) or \(M_3\)).
  • Slot 2 (Must be Female): We have 3 choices available (\(F_1, F_2,\) or \(F_3\)).
  • Slot 3 (Must be Male): Since 1 man is already placed in Slot 1, we have 2 choices left.
  • Slot 4 (Must be Female): Since 1 woman is already placed in Slot 2, we have 2 choices left.
  • Slot 5 (Must be Male): Two men are already in line, leaving us with 1 choice.
  • Slot 6 (Must be Female): Two women are already in line, leaving us with 1 choice.
Multiplying the independent choices for each slot together:
\(3 * 3 * 2 * 2 * 1 * 1 = 36\)
Why this works:
If you group the numbers by gender, it rearranges beautifully into the standard factorial approach:
\((3 * 2 * 1) * (3 * 2 * 1) = 3! * 3! = 36\)
The slot method explicitly shows how the pool of unique individuals shrinks as you move down the line, making it impossible to count non-alternating patterns like MMMFFF accidentally.
Hope this helps clear up the ambiguity!
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To all those who are confused, this will help"

An analogy

Suppose I say:

"Six books are to be arranged on a shelf, and I decide that the first three positions will contain only science books and the last three only history books. How many different arrangements are possible?"

You would not count all 6!=720 permutations, because this violates my earlier stated decision. You would count: 3!×3!=36.
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Here's my video solution:
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Long time I did not see you PGTLrowanhand. Great GMAT tutor
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