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Team A and Team B are competing against each other in a game [#permalink]

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29 May 2017, 03:38

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66% (00:53) correct
34% (01:16) wrong based on 483 sessions

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Team A and Team B are competing against each other in a game of tug-of-war. Team A, consisting of 3 males and 3 females, decides to lineup male, female, male, female, male, female. The lineup that Team A chooses will be one of how many different possible lineups?

Re: Team A and Team B are competing against each other in a game [#permalink]

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29 May 2017, 03:54

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There is only one way of forming the line MFMFMF. However, there are 3! ways of arranging the men in the line If there are 3 men (M1,M2,M3) the ways they can be arranged are: 1st 2nd 3rd M1-M2- M3 M1- M3- M2 M2- M1- M3 M2- M3- M1 M3- M1- M2 M3- M2- M1(Total 6 ways)

Similarly women can also be arranged in 6 ways.

Total possibilities of arranging both men and women are 6*6*1 = 36 ways(Option D)
_________________

Re: Team A and Team B are competing against each other in a game [#permalink]

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29 May 2017, 03:57

Men have to occupy 1st, 3rd and 5th positions. This can be done in 3*2*1 = 6 ways Women have to occupy 2nd, 4th and 6th positions. This can be done in 3*2*1 = 6 ways

Together, the above two things have to be done which can be done in 6*6 = 36 ways

Re: Team A and Team B are competing against each other in a game [#permalink]

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29 May 2017, 04:19

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mynamegoeson wrote:

Please correct me if i am wrong

M1, M2, M3, F1, F2, F3 can be arranged in 6! ways

Sent from my iPhone using GMAT Club Forum

Hi

when you say 6!, you are listing ALL the possible arrangements of 3 men and 3 women in a straight line. But as per the question, we have constraints. Men can occupy only 1st, 3rd, 5th places from start while women can occupy only 2nd, 4th, 6th places from start.

Team A and Team B are competing against each other in a game of tug-of-war. Team A, consisting of 3 males and 3 females, decides to lineup male, female, male, female, male, female. The lineup that Team A chooses will be one of how many different possible lineups?

(A) 9 (B) 12 (C) 15 (D) 36 (E) 720

Take the task of lining up the 6 competitors and break it into stages.

Stage 1: Select a competitor for the 1st position This person must be a male. Since there are 3 males to choose from, we can complete stage 1 in 3 ways

Stage 2: Select a competitor for the 2nd position This person must be a female. Since there are 3 females to choose from, we can complete stage 2 in 3 ways

Stage 3: Select a competitor for the 3rd position This person must be a male. There are 2 males remaining to choose from (since we already selected a male in stage 1), so we can complete stage 3 in 2 ways

Stage 4: Select a competitor for the 4th position This person must be a female. There are 2 females remaining to choose from. So we can complete stage 4 in 2 ways

Stage 5: Select a male for the 5th position There's only 1 male remaining. So we can complete stage 5 in 1 way

Stage 6: Select a female for the 6th position There's only 1 female remaining. So we can complete stage 6 in 1 way

By the Fundamental Counting Principle (FCP), we can complete all 6 stages (and thus create a 6-person lineup) in (3)(3)(2)(2)(1)(1) ways (= 36 ways)

Re: Team A and Team B are competing against each other in a game [#permalink]

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10 Jul 2017, 13:23

amanvermagmat wrote:

mynamegoeson wrote:

Please correct me if i am wrong

M1, M2, M3, F1, F2, F3 can be arranged in 6! ways

Sent from my iPhone using GMAT Club Forum

Hi

when you say 6!, you are listing ALL the possible arrangements of 3 men and 3 women in a straight line. But as per the question, we have constraints. Men can occupy only 1st, 3rd, 5th places from start while women can occupy only 2nd, 4th, 6th places from start.

I have a doubt here. Should we count, (m1 w1 m2 w2 m3 w3) as a line up or, (m w m w m w) as a line up?

According to the question, it says one of the lineups is (m w m w m w) Doesn't that mean, other lineups will also include (m m m w w w), (w w w m m m),... and so on?

What wording in question makes us stick to only (m w m w m w)?

Re: Team A and Team B are competing against each other in a game [#permalink]

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10 Jul 2017, 14:59

The question is really confusing. It's not clear if the suggested approach to line up 3 males and 3 females is a pattern or just one of the possible solutions. I also resolved it through 6! as the questions asked " The lineup that Team A chooses will be one of how many different possible lineups"

Even if you google the question you will find a google book, and the response is still confusing:)) It says Any of the 3 males can be first in the line and any of the 3 females can be second But why not the females start the line? I cannot find this constraint in the question

Team A and Team B are competing against each other in a game of tug-of-war. Team A, consisting of 3 males and 3 females, decides to lineup male, female, male, female, male, female. The lineup that Team A chooses will be one of how many different possible lineups?

(A) 9 (B) 12 (C) 15 (D) 36 (E) 720

I have a doubt here. Should we count, (m1 w1 m2 w2 m3 w3) as a line up or, (m w m w m w) as a line up?

According to the question, it says one of the lineups is (m w m w m w) Doesn't that mean, other lineups will also include (m m m w w w), (w w w m m m),... and so on?

What wording in question makes us stick to only (m w m w m w)?

Please correct if my thought process is wrong.

Regards, Ashygoyal

The question says that the lineup should be male, female, male, female, male, female (M-F-M-F-M-F) only. So, alternating males and females, starting with a male. Any male can take any of the three M's positions and any female can take any of the three F's positions giving different arrangements. 3 men can be arranged in 3! ways and similarly 3 women can be arranged in 3! ways. So, the answer is 3!*3! = 36.

Re: Team A and Team B are competing against each other in a game [#permalink]

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11 Jul 2017, 06:51

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Bunuel wrote:

The question says that the lineup should be male, female, male, female, male, female (M-F-M-F-M-F) only. So, alternating males and females, starting with a male. Any male can take any of the three M's positions and any female can take any of the three F's positions giving different arrangements. 3 men can be arranged in 3! ways and similarly 3 women can be arranged in 3! ways. So, the answer is 3!*3! = 36.

Answer: D.

Hope it's clear.

Sorry Bunuel, I would disagree, the question doesn't say should be made and only it clearly says

Quote:

Team A, consisting of 3 males and 3 females, decides to lineup male, female, male, female, male, female

that's why so many people found it's confusing. I get it, GMAT candidates should learn the GMAT language otherwise risk of failure on such questions is high.

The question says that the lineup should be male, female, male, female, male, female (M-F-M-F-M-F) only. So, alternating males and females, starting with a male. Any male can take any of the three M's positions and any female can take any of the three F's positions giving different arrangements. 3 men can be arranged in 3! ways and similarly 3 women can be arranged in 3! ways. So, the answer is 3!*3! = 36.

Answer: D.

Hope it's clear.

Sorry Bunuel, I would disagree, the question doesn't say should be made and only it clearly says

Quote:

Team A, consisting of 3 males and 3 females, decides to lineup male, female, male, female, male, female

that's why so many people found it's confusing. I get it, GMAT candidates should learn the GMAT language otherwise risk of failure on such questions is high.

In this context "decides to lineup" = " should lineup".
_________________

Team A and Team B are competing against each other in a game of tug-of-war. Team A, consisting of 3 males and 3 females, decides to lineup male, female, male, female, male, female. The lineup that Team A chooses will be one of how many different possible lineups?

(A) 9 (B) 12 (C) 15 (D) 36 (E) 720

We need to determine the number of ways to lineup male, female, male, female, male, female.

Since there are 3 males, we have 3 options for the first spot, and since there are 3 females, we have 3 options for the second spot. Then we have 2 options for the third spot, 2 options for the fourth, and 1 option for each of the last two spots. Thus, the number of ways to lineup that group is 3 x 3 x 2 x 2 x 1 x 1 = 36.

Answer: D
_________________

Scott Woodbury-Stewart Founder and CEO

GMAT Quant Self-Study Course 500+ lessons 3000+ practice problems 800+ HD solutions

Re: Team A and Team B are competing against each other in a game [#permalink]

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05 Nov 2017, 18:22

ganand wrote:

Team A and Team B are competing against each other in a game of tug-of-war. Team A, consisting of 3 males and 3 females, decides to lineup male, female, male, female, male, female. The lineup that Team A chooses will be one of how many different possible lineups?

(A) 9 (B) 12 (C) 15 (D) 36 (E) 720

Line up - M1 F1 M2 F2 M3 F3; M1 can be any of the 3 males - 3 choices M2 can be any of the 2 remaining males - 2 choices M3 has to be the last male - 1 choice Therefore the total arrangement for males = 3 * 2 * 1 = 6 Similarly, F1 can be any of the 3 females - 3 choices F2 can be any of the 2 remaining females - 2 choices F3 has to be the last female - 1 choice Therefore the total arrangement for females = 3 * 2 * 1 = 6 Now the total arrangement possible = 6 * 6 = 36

OR

3 males and 3 females can be arranged in 6! ways = 720 ways but the arrangement has to be M F M F M F. This arrangement can happen in 6!/3!*3! ways = 20 ways Hence the total ways = 20/720 = 1/36 But to get this unique combination of M1 F1 M2 F2 M3 F3 we should have the numerator as 1. Hence, 36 ways.

Re: Team A and Team B are competing against each other in a game [#permalink]

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06 Nov 2017, 20:51

Bunuel wrote:

cbh wrote:

Bunuel wrote:

The question says that the lineup should be male, female, male, female, male, female (M-F-M-F-M-F) only. So, alternating males and females, starting with a male. Any male can take any of the three M's positions and any female can take any of the three F's positions giving different arrangements. 3 men can be arranged in 3! ways and similarly 3 women can be arranged in 3! ways. So, the answer is 3!*3! = 36.

Answer: D.

Hope it's clear.

Sorry Bunuel, I would disagree, the question doesn't say should be made and only it clearly says

Quote:

Team A, consisting of 3 males and 3 females, decides to lineup male, female, male, female, male, female

that's why so many people found it's confusing. I get it, GMAT candidates should learn the GMAT language otherwise risk of failure on such questions is high.

In this context "decides to lineup" = " should lineup".

For me, the last line of the question created the confusion.

"The lineup that Team A chooses will be one of how many different possible lineups?"

So I though M F M F M F was one kind of line up and hence I found the other type of line ups using 6!. Understanding such questions become really difficult during the exam.