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28 Aug 2017, 23:38
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Difficulty:
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77% (01:39) correct
23%
(02:09)
wrong
based on 180
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A non-symmetrical arrow point exists such that the angle of the back of the arrow point equals 105°, similar to the diagram above. What is the sum of internal angles a, b, and c?
A. 105°
B. 125°
C. 127.5°
D. 145°
E. 180°
Attachment:
Arrow.png [ 11.39 KiB | Viewed 5236 times ]
29 Aug 2017, 07:15
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Let the Triangle be ABC . Join A and C . Let angle O = 105
Now angle A= x + a
and Angle C = y +c
Therefore triangle AOC = x+ 105 + y = 180
x + y = 75
Therefore in triangle ABC = x + a + b +c + y =180
as x + y = 75
therefore a + b + c = 105
Now angle A= x + a
and Angle C = y +c
Therefore triangle AOC = x+ 105 + y = 180
x + y = 75
Therefore in triangle ABC = x + a + b +c + y =180
as x + y = 75
therefore a + b + c = 105
chaitanya1317
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29 Aug 2017, 07:50
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Connect Point of angle A and angle C to form a triangle.
This also forms another smaller triangle with one angle as 105. The other two angles have to be 75.
Now you can notice that in the bigger triangle, sum of a , b, c will be 180 - 75 = 105. That's your answer - A
This also forms another smaller triangle with one angle as 105. The other two angles have to be 75.
Now you can notice that in the bigger triangle, sum of a , b, c will be 180 - 75 = 105. That's your answer - A
