If a square has a side of length s and a diagonal of length d, then s2

Question

If a square has a side of length s and a diagonal of length d, then s^2/d^2 =

(A) 1/4 
(B) √2/4 
(C) 1/2
(D) √2/2 
(E) 2/1

Richak91 · Answer

Diagonal d of a square =  s\sqrt{2}

Therefore, s^2/d^2 = s^2/( (s\sqrt{2} )^2 = 1/2

Answer : C

manishgmat1 · Answer

diag=root 2 
d= root 2*2
s^2/ d^2== 1/2

raki99 · Answer

Diagonal d of a square = s2√s2

Therefore, s^2/d^2 = s^2/((s2√(s2)^2 = 1/2

Answer : C

generis · Answer

Another way is to choose numbers.

Let  s = 2 , then  d = s \sqrt{2} , so 
 d = 2\sqrt{2}

\frac{s^2}{d^2}  =  \frac{2^2}{(2\sqrt{2})^2}  =  \frac{4}{8} = \frac{1}{2}

Answer C

ScottTargetTestPrep · Answer

We may recall that diagonal = side√2; thus:

d = s√2

s/d = 1/√2

s^2/d^2 = (1/√2)^2 = 1/2

Answer: C

rajdavezz99 · Answer

In case you can't recall the direct formula, start with the Pythagoras theorem:

a^2 + b^2 = c^2, where a and b are sides of a right-angled triangle and c is the hypotenuse.

For a square, since all sides are equal, you get

s^2 + s^2 = d^2

And then the solution is as mentioned above by others.

Posted from my mobile device

bumpbot · Answer

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If a square has a side of length s and a diagonal of length d, then s2

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If a square has a side of length s and a diagonal of length d, then s2

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