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17 Oct 2017, 08:14
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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Question Stats:
77% (01:18) correct
23%
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wrong
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Train T leaves town A for town B and travels at a constant rate of speed. At the same time, train S leaves town B for town A and also travels at a constant rate of speed. Town C is between A and B. Which train is traveling faster? Towns A, C, and B lie on a straight line.
(1) Train S arrives at town C before train T.
(2) C is closer to A than to B.
(1) Train S arrives at town C before train T.
(2) C is closer to A than to B.
17 Oct 2017, 12:09
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Bunuel
Let the speed of train T be \(u\), time taken to reach C be \(t_1\) and distance between A & C be \(x\)
Let the speed of train S be \(v\), time taken to reach C be \(t_2\) and distance between B & C be \(y\)
we need to find which speed between \(u\) & \(v\) is greatest
Statement 1: implies \(t_2<t_1\) \(=> \frac{y}{v}<\frac{x}{u}\)
or \(u<\frac{x}{y}v\). Now we need to know the ratio of \(\frac{x}{y}\) to determine whether \(u\) or \(v\) is greater. But the value of \(x\) & \(y\) is not given. Hence Insufficient
Statement 2: implies that \(x<y => ut_1<vt_2\). but nothing given about \(u\), \(v\) or \(t_1\) & \(t_2\). Hence Insufficient
Combining 1 & 2 we get \(x<y => \frac{x}{y}<1\), multiply both sides by \(v\) to get \(\frac{x}{y}v<v\)
from statement 1 we get \(u<v\). Hence sufficient
Option C
23 Oct 2017, 10:35
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C, I had to do this one visually. So I drew a line with points A and B at each end. I drew T over point A and drew S over point B. I drew a point C halfway in between A and B, but I reminded myself that C could be anywhere between A and B.
St 1, says train S arrives at C before train T. Insufficient, but if we need the location of point C in relation to A and B, then that would suffice.
St 2, says point C is closer to point A.
-Insufficient by itself, but nevertheless, I crossed out where I had drawn C and moved it closer to A.
1+2, Since C is closer to point A and train S which is travelling a farther distance beats train T, then it must be the faster train.
St 1, says train S arrives at C before train T. Insufficient, but if we need the location of point C in relation to A and B, then that would suffice.
St 2, says point C is closer to point A.
-Insufficient by itself, but nevertheless, I crossed out where I had drawn C and moved it closer to A.
1+2, Since C is closer to point A and train S which is travelling a farther distance beats train T, then it must be the faster train.
