A certain tin contains exactly 10 identically shaped gumdrops, of whic

Question

A certain tin contains exactly 10 identically shaped gumdrops, of which 2 are cherry, 2 are lemon, 2 are grape, 2 are cinnamon and 2 are strawberry. If 2 gumdrops are randomly selected, one at a time and without replacement, what is the probability that the second gumdrop is the same flavor as the first?

A. \(\frac{1}{45}\)

B. \(\frac{1}{25}\)

C. \(\frac{1}{9}\)

D. \(\frac{1}{5}\)

E. \(\frac{2}{5}\)

A.  \frac{1}{45}

B.  \frac{1}{25}

C.  \frac{1}{9}

D.  \frac{1}{5}

E.  \frac{2}{5}

sananoor · Accepted Answer

if we simplify question, its simply asking that what is the probability of selecting a pair out of 5 pairs?
favorable outcome/total outcome--->5C1/10C2 = 5/45= 1/9...C is the answer

hasnain3047 · Answer

selecting first gumdrop 2/10 = 1/5
selecting second gumdrop 1/9
so total probability of first event = 1/5 * 1/9 = 1/45
now there are 5 identical event which yield probability 1/45, so,
total probability = 6*1/45 =  1/9 
 Answer C

CounterSniper · Answer

no of ways to select the 1st gumdrop =10
no of ways to select the second gumdrop=1

required probability=10*1/10*9=1/9

pushpitkc · Answer

This question can be solved by using logic:

Once the first gum-drop has been selected, in order to select the second gumdrop(with the same 
flavor as the first), one could choose only 1 of the gumdrop from the remaining 9 gumdrops.

Therefore, the probability that the second gumdrop is of the same flavor as the first is  \frac{1}{9}   (Option C)

bumpbot · Answer

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A certain tin contains exactly 10 identically shaped gumdrops, of whic

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A certain tin contains exactly 10 identically shaped gumdrops, of whic

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