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roysaurabhkr
Answer is B

Quick trick: Side opposite to the biggest angle in a triangle is biggest. (And Side opposite to the smallest angle in a triangle is smallest)
In Triangle ACD:

Statement A
x= 50 degree. Thus, angle ACD = 50 degree. No conclusion can be drawn about the other angles and hence the relative size of the sides.

Statement B angle Z = 70 degree.
The sum of remaining angles in the triangle = 110 degree.
Thus one of the remaining two angles is definitely < 70 degree.
Thus, angle z is not the smallest angle
Thus we know for sure that the side opposite to angle Z is not the smallest.

Hence answer B.


It is possible that the other two angles could be 100 & 10, 90 & 20 or 80 & 30.
Can you please explain how you eliminated the above-mentioned possibilities?


Best,
Cj
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roysaurabhkr
Answer is B

Quick trick: Side opposite to the biggest angle in a triangle is biggest. (And Side opposite to the smallest angle in a triangle is smallest)
In Triangle ACD:

Statement A
x= 50 degree. Thus, angle ACD = 50 degree. No conclusion can be drawn about the other angles and hence the relative size of the sides.

Statement B angle Z = 70 degree.
The sum of remaining angles in the triangle = 110 degree.
Thus one of the remaining two angles is definitely < 70 degree.
Thus, angle z is not the smallest angle
Thus we know for sure that the side opposite to angle Z is not the smallest.

Hence answer B.


It is possible that the other two angles could be 100 & 10, 90 & 20 or 80 & 30.
Can you please explain how you eliminated the above-mentioned possibilities?


Best,
Cj

Hi Cj,

The side opposite the smallest angle in a triangle will be the smallest side.

ST1: we know CAD=50, so ACD+ADC=130. If ADC<50, then it will be the smallest angle and thus, the side opposite to it will be the smallest.
If ADC > 50, then AC won't be the smallest. We can't determine ADC for sure, so not sufficient.

ST2: z=70 => CAD+ACD = 110. If CAD=ACD, then each angle equals to 55. If, they are not equal then for an increment of 1 in one angle, the other angle will decrease by 1, since their sum is constant. So, for sure one of the angles will be < 56. This means that z is not the smallest angle. Thus, AC is not the smallest side.
Sufficient.
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Bunuel

In the figure shown below, the line segment AD is parallel to the line segment BC. Is AC the shortest side of triangle ACD?

(1) x = 50
(2) z = 70
Attachment:
2018-11-06_1238.png

Solution:
Pre Analysis:
  • In the given figure, line AD is parallel to side BC
  • This means \(\angle CAD=\angle BCA=x^o\) (alternate angle)
  • We area sked if side AC is the shortest side of triangle ACD or not
  • For this, \(\angle ADC=z^o\) has to be the smallest angle of the three angles in triangle ACD

Statement 1: x = 50
  • If \(\angle A=x=50^o\) then sum of the rest of the two has to be 130
  • Let us take 2 cases:
    • \(\angle A=50, \angle C=50\), \(\angle D=30\)
      • In this case, \(\angle D\) is the smallest. Thus, side AC is the smallest
    • \(\angle A=50, \angle C=30\), \(\angle D=50\)
      • In this case, \(\angle D\) is not the smallest. Thus side AC is not the smallest
  • Thus, statement 1 alone is not sufficient and we can eliminate options A and D

Statement 2: z = 70
  • If \(\angle D=z=70^o\) then sum of the rest of the two has to be 110
  • We can infer from this that rest of the two angles cannot be both greater than 70
  • Thus, we can say that side AC is not the smallest side
  • Thus, statement 2 alone is sufficient


Hence the right answer is Option B
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