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The extremes of the other 2 machines are either all 7 per hour in which case the average will be
(7+7+7+8)/4= 7.25

Or

all 8per hour making the overall average to be
(7+8+8+8)/4= 31/4=7.75

Hence the answer cannot be lower than 7.25 per hour making A the answer

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VeritasKarishma chetan2u niks18 gmatbusters Gladiator59 GMATPrepNow EMPOWERgmatRichC

I understood the above solutions; my query is:
Is there a way to skip long division? The answers seems so close by to approximate.
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Hi adkikani,

Since the answer choices are so 'close' to one another, we have to do enough 'precision' math to make sure that we have the correct answer (if you approximate the answer incorrectly, then you might convince yourself that one of the wrong answers is correct). Thankfully, the work here isn't too bad - and you really just have to think about no more than two possibilities:

We know the exact rates of 2 of the 4 machines. The FASTEST processes 7 cards in an hour and the SLOWEST processes 8 cards in an hour. We don't know the exact speeds of the other two machines, but we know that they are some rate BETWEEN 7 cards and 8 cards per hour. Thus, there will be a limit to how fast or how slow the overall average could be. By extension, the correct answer will either be TOO FAST or TOO SLOW for what that group is capable of averaging (meaning that the correct answer will be Answer A or Answer E).

Even though we can't have the other two machines working at 7 cards/hour, IF they did work at that rate, then the average would be (7+7+7+8)/4 = 29/4 = 7.25 cards/hour. There is NO POSSIBLE OPTION for the average to be a lower number than that (those other two numbers can only get bigger than 7). At this point, we can stop working; 7.2 is NOT a possibility, so it has to be the answer to this question.

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HKD1710
There are 4 card-processing machines in an office. The fastest of these machines processes x cards in 7 hours and the slowest processes x cards in 8 hours. Which of the following could NOT be the average time per machine for each of the 4 machines to process x cards?

(A) 7.2
(B) 7.3
(C) 7.5
(D) 7.6
(E) 7.7


The average of the two machines that we know is 7.5.
We know we need an extreme value, so B, C, and D are out.
7.2 deviates from 7.5 by 0.3.
7.7 deviates from 7.5 by 0.2.
How would it be possible to get to 7.7 but not be possible to get to 7.2? E is out.

Answer choice A.
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4 machines working together will take much much lesser than 7 hours if they need to process only x machines (and not 4x machines), what am I missing ?

I took LCM of 56
thus if 7,7,7,8 gives 31 units thus time taken - 56/31
if 7,8,8,8 then time taken 56/29

what am I missing
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4 machines working together will take much much lesser than 7 hours if they need to process only x machines (and not 4x machines), what am I missing ?

I took LCM of 56
thus if 7,7,7,8 gives 31 units thus time taken - 56/31
if 7,8,8,8 then time taken 56/29

what am I missing

You are finding the combined time for 4 machines working together.

The question asks for the average of the 4 separate individual times.

Have you checked the discussion above?
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