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Rachel and Rob live 190 miles apart. They both drive in a straight line toward each other to meet for tea. If Rachel drives at 50 mph and Rob drives at 70 mph, then how many miles apart will they be exactly 45 minutes before they meet?

A. 50
B. 60
C. 70
D. 90
E. 100

We can let t = the time if takes to meet and create the equation:

50t + 70t = 190

120t = 190

t = 190/120 = 19/12 hours or 19/12 x 60 = 95 minutes

So each will have driven for 50 minutes when it is 45 minutes before they meet. Therefore, together they will have driven (50 + 70) x 50/60 = 120 x 50/60 = 2 x 50 = 100 miles. Since the total distance is 190 miles, they will be 190 - 100 = 90 miles apart when it is exactly 45 minutes before they meet.

Alternate solution:

Notice that the distance between the two decreases by 50 + 70 = 120 miles every hour. Since they have to drive 45 more minutes to meet when it is exactly 45 minutes before they meet, they must be (50 + 70) x 45/60 = 120 x 45/60 = 2 x 45 = 90 miles apart.

Answer: D
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Let X be meeting point.
Rob------------------------------------X-------------------------------------------Rachel

45 mins prior to meeting point, Rachel would have travelled (3/4 * 50) miles from right of X to X
and Rob would have travelled (3/4 * 70) miles from left of X to X.

so distance apart = (3/4) * 50 + (3/4) * 70 = (3/4) * 120 = 90 miles
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total speed = 70+50 mph ( as they are moving towards each other)
total distance = 190 miles
they are covering 120 miles in 1hr
so the remaining miles to cover is 190-120 = 70 miles
time taken to cover 70 miles is t = 70/120*60 = 35 mins (*60 for minute conversion)
it's evident that they are covering 2 miles per minute hence 45*2 = 90 miles
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Let \(d\) be the distance between Rachel and Rob, which is initially \(190\) miles.
Rachel drives at a speed of \(50\) mph and Rob drives at a speed of \(70\) mph.
Since they are driving towards each other, their relative speed is the sum of their speeds:
\(50 + 70 = 120\) mph.

Let \(t\) be the time in hours until they meet. Then,

\(120t = 190\)

\(t = \frac{190}{120} = \frac{19}{12}\) hours.

We want to find the distance between them 45 minutes before they meet.
45 minutes is \(\frac{45}{60} = \frac{3}{4}\) hours.
So we want to find the distance between them at time
\(t - \frac{3}{4} = \frac{19}{12} - \frac{3}{4} = \frac{19}{12} - \frac{9}{12} = \frac{10}{12} = \frac{5}{6}\) hours.
In \(\frac{5}{6}\) hours, Rachel travels
\(50 \cdot \frac{5}{6} = \frac{250}{6} = \frac{125}{3}\) miles.
In \(\frac{5}{6}\) hours, Rob travels
\(70 \cdot \frac{5}{6} = \frac{350}{6} = \frac{175}{3}\) miles.
The total distance they have traveled is
\(\frac{125}{3} + \frac{175}{3} = \frac{300}{3} = 100\) miles.
Therefore, the distance between them at that time is
\(190 - 100 = 90\) miles.

Final Answer: The final answer is \(\boxed{90}\)
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