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Option: C
time taken for filling => 60 mins/4 = 15 mins (since all taps fill at equal rate)
Total activity time (time to fill + time to empty tank) = 30 mins
therefore, Time taken to empty tank by 2 outlets = 30 - 15 = 15 mins
Since outlets empty at equal rate, time needed by each outlet to empty tank = 15x2 = 30 mins
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Solution



Given:
In this question, we are given
    • In a certain task, a person has to fill an empty tank using four taps, each of which can fill the entire empty tank in 1 hour.
    • Once the tank is filled completely, he needs to empty the tank using two outlets, at the bottom of the tank.
    • Both the outlets can empty the full tank in same time.
    • The total time taken by the person to finish the task is 30 minutes.

To find:
We need to determine
    • The amount of time does an outlet tap take to empty a full tank.

Approach and Working:
As each inlet tap can fill the tank in 1 hour, while 4 taps are working together, the tap will be filled in \(\frac{1}{4}\) hour = 15 minutes
    • Hence, in (30 – 15) = 15 minutes the two outlet taps can empty the tank.
    • As both outlet taps can empty the tank at the same time, each of them individually can empty the tank in 15 x 2 = 30 minutes or \(\frac{1}{2}\) hour.

Hence the correct answer is Option C.

Answer: C


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I approached the problem this way.. plz let me know my mistake:

Rate of all 4 fill taps = 1/4
Rate of 2 drain taps = 2/x

Total work = 1 and time taken = 30/60 so, rate = 1/ (30/60) —> 60/30

1/4 - 2/x = 2

-2/x = 2-1/4


-2/x = 7/4

X=-8/7 —> rate of 1 drain tap —> time taken for 2 = 7/8 * 2 = 14/8 = 1.75 h

What am I doing wrongly here ? EgmatQuantExpert
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