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exc4libur
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An elevator has a weight limit of 630 kg. It is carrying a group of people of whom the heaviest weighs 101 kg and the lightest weighs 53 kg. What is the maximum possible number of people in the group?

A. 6
B. 9
C. 10
D. 11
E. 12

630-101-53=476
476/53~8...
8+2=10
(C)

I get the logic which is to use the lowest possible weight, but how is 476/53 = ~8 when it should be 9? In which case the answer is 11.
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Total weight limit: 630

Heaviest weighs: 101 kg and the lightest weighs: 53 kg

For the maximum number of possible people, the weigh of those people should be as low as possible but greater than 53.

630 - (101 + 53 = 154) = 476

For remaining fo 476 kg weight, we can have maximum 8 people [60 * 8 = 480]. Total number of people: 2 + 8 = 10

Answer C
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it's close to 9 but not fully 9 people. you can't have .98 of a person. so the closest whole number of people is 8
+ the two you counted earlier weighing 101 and 53 each.

CEdward
exc4libur
nick1816
An elevator has a weight limit of 630 kg. It is carrying a group of people of whom the heaviest weighs 101 kg and the lightest weighs 53 kg. What is the maximum possible number of people in the group?

A. 6
B. 9
C. 10
D. 11
E. 12

630-101-53=476
476/53~8...
8+2=10
(C)

I get the logic which is to use the lowest possible weight, but how is 476/53 = ~8 when it should be 9? In which case the answer is 11.
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