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Raj30
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Deconstructing the Question

We are comparing the standard deviation of the y-values generated by each linear equation as x takes all integer values from 1 to 100.

For a linear transformation of the form \(y=ax+b\), the standard deviation changes by a factor of \(|a|\). The constant term \(b\) only shifts all values and does not affect spread.

So we only need to compare the absolute value of the coefficient of x.

Step-by-step

In choice A,

\(y=\frac{x}{3}\)

the coefficient of x is

\(\frac{1}{3}\)

In choice B,

\(y=\frac{x}{2}+40\)

the coefficient of x is

\(\frac{1}{2}\)

The \(+40\) does not affect the standard deviation.

In choice C,

\(y=x\)

the coefficient is

\(1\)

In choice D,

\(y=2x+50\)

the coefficient is

\(2\)

The \(+50\) does not affect the standard deviation.

In choice E,

\(y=3x-20\)

the coefficient is

\(3\)

The \(-20\) does not affect the standard deviation.

Now compare the absolute values:

\(\frac{1}{3}, \frac{1}{2}, 1, 2, 3\)

The greatest is \(3\), so choice E gives the greatest standard deviation.

Answer: E
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Raj30
Each of the following linear equations defines y as a function of x for all integers x from 1 to 100. For which of the following equations is the standard deviation of the y-values corresponding to all the x-values the greatest?


A) y = x/3
B) y = x/2+40
C) y = x
D) y = 2x + 50
E) y = 3x − 20

A higher SD means the numbers are more spread out on the number line.

Consider y = x. Here y is a set of numbers from 1 to 100. It has a certain SD, say S.
When we divided every term of this list of 100 numbers by 2 or 3, the numbers come close together on the number line. So for options (A) and (B), the numbers will be much closer together and their SD will be smaller than S. Recall that adding a fixed constant to each number of the list does not change the SD. Hence the +40 in option (B) has no impact on its SD.

When we multiply each term of this list by 2, the numbers spread out on the number line and when we multiply by 3, the numbers spread out even further. Hence SD of option (D) will be more than S and that of option (E) will be even higher. Again, adding or subtracting a constant from each term has no impact on SD.

Hence option (E) will have the greatest SD.

Answer (E)
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