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Bunuel
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Does the point (p, q) lie on the line y = mx + c (p, m, and c are non- 19 Jul 2019, 00:41
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D
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75% (hard)

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42% (01:37) correct 58% (01:52) wrong based on 212 sessions

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Does the point (p, q) lie on the line y = mx + c (p, m, and c are non-zero)?

(1) The line y = mx – c passes through the point (p, q).
(2) The line y = –mx + c passes through the point (p, q).
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D
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Does the point (p, q) lie on the line y = mx + c (p, m, and c are non- Updated on: 23 Jul 2019, 01:42
Originally posted by Kinshook on 23 Jul 2019, 01:06.
Last edited by Kinshook on 23 Jul 2019, 01:42, edited 1 time in total.
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Bunuel
Does the point (p, q) lie on the line y = mx + c (p, m, and c are non-zero)?

(1) The line y = mx – c passes through the point (p, q).
(2) The line y = –mx + c passes through the point (p, q).
Show more

Given: p, m, and c are non-zero
Asked: Does the point (p, q) lie on the line y = mx + c ?

(1) The line y = mx – c passes through the point (p, q).
Line y=mx-c is parallel to y=mx+c but they are same when c=0 which is not the case.
so no intersection point exists.
If (p,q) lie on line y=mx+c => (p,q) does not lie on y=mx-c
SUFFICIENT

(2) The line y = –mx + c passes through the point (p, q).
Intersection point of y=mx+c and y=-mx+c is (0,c)
Since p<>0 indicates that (p,q) is not the intersection point of lines y=mx+c and y=-mx+c.
If (p,q) lie on line y=mx+c => (p,q) does not lie on y=-mx+c
SUFFICIENT

IMO D
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Does the point (p, q) lie on the line y = mx + c (p, m, and c are non- 23 Jul 2019, 01:41
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Kinshook
Bunuel
Does the point (p, q) lie on the line y = mx + c (p, m, and c are non-zero)?

(1) The line y = mx – c passes through the point (p, q).
(2) The line y = –mx + c passes through the point (p, q).

Given: p, m, and c are non-zero
Asked: Does the point (p, q) lie on the line y = mx + c ?

(1) The line y = mx – c passes through the point (p, q).
Line y=mx-c is parallel to y=mx+c so no intersection point exists. They are same only when c=0 which is not the case.
If (p,q) lie on line y=mx+c => (p,q) does not lie on y=mx-c
SUFFICIENT

(2) The line y = –mx + c passes through the point (p, q).
Intersection point of y=mx+c and y=-mx+c is (0,c)
Since p<>0 indicates that (p,q) is not the intersection point of lines y=mx+c and y=-mx+c.
If (p,q) lie on line y=mx+c => (p,q) does not lie on y=-mx+c
SUFFICIENT

IMO D
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Does the point (p, q) lie on the line y = mx + c (p, m, and c are non- 26 Jul 2019, 12:34
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Does the point (p, q) lie on the line y = mx + c (p, m, and c are non-zero)?

(1) The line y = mx – c passes through the point (p, q).
(2) The line y = –mx + c passes through the point (p, q).
Show more

Can someone else provide an explanation? I am bad at Co-ordinate Geometry (But I am learning and will not leave it) and I cannot visualize this. Thank you!
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Does the point (p, q) lie on the line y = mx + c (p, m, and c are non- 01 Aug 2019, 01:58
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Statement 1 : y=mx+c and y=mx-c have the same slope and hence are parallel. If y=mx-c passes through (p,q) then y=mx+c can not pass through as well. SUFFICIENT


Statement 2 : y=-mx+c and y=mx+c have only one common point of intersection which is c. This is because they have opposite slopes and only meet at c. (0,c) can not be p,q since p is non-zero and at point (0,c) the x cordinate is 0.They can not also share p,q as common points of intersection. SUFFICIENT

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Does the point (p, q) lie on the line y = mx + c (p, m, and c are non- 10 Mar 2020, 23:18
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How is the intersection point (0,c) i understand that the slopes are opposite and hence they can meet at c, but why is the point (0,c) and not (c,0)
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Does the point (p, q) lie on the line y = mx + c (p, m, and c are non- 19 Jun 2020, 08:12
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If the slopes are opposite then lines are perpendicular right?

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Does the point (p, q) lie on the line y = mx + c (p, m, and c are non- 12 Aug 2022, 11:56
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