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Does the point (p, q) lie on the line y = mx + c (p, m, and c are non-zero)?

(1) The line y = mx – c passes through the point (p, q).
(2) The line y = –mx + c passes through the point (p, q).

Can someone else provide an explanation? I am bad at Co-ordinate Geometry (But I am learning and will not leave it) and I cannot visualize this. Thank you!
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Statement 1 : y=mx+c and y=mx-c have the same slope and hence are parallel. If y=mx-c passes through (p,q) then y=mx+c can not pass through as well. SUFFICIENT


Statement 2 : y=-mx+c and y=mx+c have only one common point of intersection which is c. This is because they have opposite slopes and only meet at c. (0,c) can not be p,q since p is non-zero and at point (0,c) the x cordinate is 0.They can not also share p,q as common points of intersection. SUFFICIENT

ANSWER IS D
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How is the intersection point (0,c) i understand that the slopes are opposite and hence they can meet at c, but why is the point (0,c) and not (c,0)
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If the slopes are opposite then lines are perpendicular right?

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Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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