Any decimal that has only a finite number of nonzero digits is a termi

Question

Any decimal that has only a finite number of nonzero digits is a terminating decimal.

For example, 10, 0.23, and 8.107 are three terminating decimals. If n and m are positive integers and the ratio n/m is expressed as a decimal, is n/m a terminating decimal?

(1) n is a three-digit number divisible by 10.

(2) m = 5

Bunuel · Answer

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rishab0507 · Answer

D

Terminating decimal is which has only 2 and 5 in denominator. 
statement 1 : 10 is 2*5 and N is divisible by 10 it means there is nothing else in numerator which we need to reduce and denominator has only 2s and 5s, which is desired for terminating decimal. : Sufficient

Statement 2 : M has 5, which is required for terminating decimal : Sufficient

Archit3110 · Answer

#1
n = 100a+10b+c will be a terminating decimal when divided by 10 as factor of 10 ; 2 *5
suffcient
#2
when m=5 again n being a +ve integer will be a terminating decimal
sufficeint
IMO D

gotoeurope · Answer

(2) is sufficient because m is denominator and if denominator is multiple of 2 or 5, the decimal of the fraction is terminating decimal regardless of what n is

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philipssonicare · Answer

1) 100/3=33.3333333, not terminating
 100/100=1, terminating
 BCE 
2) x/5
So long as the fully simplified denominator has only 2s and 5s as prime factors, the decimal is terminating
 B

EncounterGMAT · Answer

n/m will be a  terminating decimal  if the denominator is of the form  2^n  5^m , where m and n are non-negative integers

(1) n is a three-digit number divisible by 10.
n= any multiple of 10 and m= any number
if m=  2^x  5^y = terminating, else non-terminating
different answers...................INSUFFICIENT

(2) m = 5
= 2^0  5^1 ............SUFFICIENT

Answer is Option B.

gotoeurope · Answer

Hi, we can’t say the fraction can be a terminating decimal only with (1)
If n is 100 following (1), and m is 3? 
It is not a terminating decimal.

Decision factor for terminating decimal is only denominator.

Posted from my mobile device

EncounterGMAT · Answer

hey! thanks for the explanation. I understood where I went wrong. +1 kudos
P.S: I have corrected my post

Bunuel · Answer

Official Explanation

This question takes some time to define a terminating decimal and asks us whether n/m such a decimal is. Let's look at the statements, separately first.

Statement (1) tells us that n is a number such as 200 or 210. Meanwhile, m could be any positive integer, such as 3. We get a terminating decimal from n/m = 210/3 = 70, but not from 200/3, which will have a repeating 3. Therefore, the possible cases include conflicting possible answers, and Statement (1) is insufficient.

Statement (2) tells us that m is 5. Meanwhile, we know nothing about n, except that it's a positive integer. If n=10, then n/m = 10/5 = 2, and we have a terminating decimal. If n=3, then n/m = 3/5 = 0.6. That, too, is a terminating decimal. No matter what n is, when divided by m it will be an integer or end in .2, .4, .6, or .8. Therefore, n/m will also be a terminating decimal. We can answer definitively, so Statement (2) is sufficient.

The correct answer is (B).

Bunuel · Answer

Video Explanation

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bumpbot · Answer

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Any decimal that has only a finite number of nonzero digits is a termi

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