Angad97
Tom, Amanda and Harry working alone can finish a task in 4, 6, and 12 hours respectively. Tom, Amanda and Harry start working together and work for 1 hour, then Tom left and then Amanda and Harry work together for 1 hour, then Amanda left and the rest of the work is done by Harry alone. If the task was started at 10:00 am, then at what time does the task get completed?
(A) 2:30 pm
(B) 3:00 pm
(C) 3:30 pm
(D) 4:00 pm
(E) 4:30 pm
SOLUTION
so take the lcm of 4,6,12
which is 12 this is work lets assume
rate=work /time
so
tom=(12/4)=3
amanda=(12/6)=2
harry=(12/12)=1
now
add the rates they said first 1 hour t,a ,h worked together
3+2+1=6
this is from 10 am to 11 am
now tom leaves
so a and h
its 2+1=3
from 11am to 12 am
so from 10am to 12 am the rate of work done is 6+3=9
now we should know how much left over work is done by harry (so do total work( minus -)the work from 10am to 12 am)
now as we assume the work to be 12 the trick is do 12-9=3(try this with any combination of numbers ull get correct ans )
now the rate harry is 1 and time=work/rate => 3/1
so now its 3 hours from 12 am
and is c 3:00 am