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There are only four values of x for which x (x+1) is a multiple of 36 and these are 35,36,71 and 72. All these 10 values are not multiples of 12 AND 9. AND not OR. Confused by the answer here


Bunuel
If x is an integer and \(1 ≤ x ≤ 100\), what is the probability that \(x(x + 1)\) is a multiple of 12 and 9?

(A) 1/10
(B) 1/20
(C) 2/25
(D) 11/100
(E) 17/100


Are You Up For the Challenge: 700 Level Questions
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MissionAdmit
There are only four values of x for which x (x+1) is a multiple of 36 and these are 35,36,71 and 72. All these 10 values are not multiples of 12 AND 9. AND not OR. Confused by the answer here


Bunuel
If x is an integer and \(1 ≤ x ≤ 100\), what is the probability that \(x(x + 1)\) is a multiple of 12 and 9?

(A) 1/10
(B) 1/20
(C) 2/25
(D) 11/100
(E) 17/100


Are You Up For the Challenge: 700 Level Questions

Let's say we take the number 27*28 as x(x+1)
Now the question states that 27*28 should be a multiple of 9 and 12.
So
27*28 divided by 12 gives 63
27*28 divided by 9 gives 84

Hence 27*28 and the other numbers are divisible by 12 and 9 both as a multiple of x(x+1) together.
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Bunuel
If x is an integer and \(1 ≤ x ≤ 100\), what is the probability that \(x(x + 1)\) is a multiple of 12 and 9?

(A) 1/10
(B) 1/20
(C) 2/25
(D) 11/100
(E) 17/100


Are You Up For the Challenge: 700 Level Questions

To be a multiple of 12 & 9 --> to be a multiple of LCM(12, 9) = 36
--> We have to find that x(x+1) is a multiple of 36

Total = 100
Note that, one of x or (x+1) should be a multiple of 9 and the other should be a multiple of 4 or one should be a multiple of 36
--> Favorable values = {8*9, 27*28, 35*36, 36*37, 44*45, 63*64, 71*72, 72*73, 80*81, 99*100} = 10

Required Probability = 10/100 = 1/10

IMO Option A
Multiples of 4 and 9 less than 100 are given below.

Multiples of 4 = 4,8,12,16,20,24,28,32, 36,40,44,48,52,56,60,64,68,72,76,80, 84, 88,92,96,100

Multiples of 9 = 9,18,27,36,45,54,63,72,81,90,99.

Let’s look for consecutive numbers (8,9) , (27,28) , (44,45) , (63,64) , (80,81) and (99,100)

We know that x(x+1) is a multiple of 36. Either x is 36 or x+1 is 36.

We get, (35,36) or (36,37). Another multiple of 36 is 72. We get, (71,72) or (72,73).

Total count is 10.

Probability = 10/100 = 1/10
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