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P(Accepted at No more than 2 tries)
= P(accepted at first try) + P(accepted at second try)
= 0.15 + (1-0.15)*(0.20)
= 0.15 + (0.85)*(0.20)
= 0.15 + 0.17
= 0.32
Probability is 32%

Answer: C
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Hi everyone!

Can anyone please clear-up how the probability for acceptance for the 2nd time applicant is 17%?
Why is it different from 20% in the first place? I see that its is being calculated on 85% which is the (1 - 0.15) from the first application, but what is the reason for that?


Thanks
Shivam
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Shivm44
Hi everyone!

Can anyone please clear-up how the probability for acceptance for the 2nd time applicant is 17%?
Why is it different from 20% in the first place? I see that its is being calculated on 85% which is the (1 - 0.15) from the first application, but what is the reason for that?


Thanks
Shivam

Second time it becomes 85/100 * 20/100 = 17 /100

hope it's clarifies
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I solved it as below without prior knowledge of the topic: (took me 1:07)

Assume we have 100 candidates who apply to the college
Round 1 - Only 15% ie., 15 candidates are selected.

Meaning 85 are not selected in Round 1.
Now assuming all 85 reapply; Round 2 we have 20% of 85 who are accepted ie, 17.

In total, we have 15+17 = 32 candidates selected from an overall pool of 100 after reapplying (or applying twice)

Hence 32% would be the probability that he would not have to apply more than twice to be selected :)
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