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Kritisood
If a and b are integers then what is the remainder when \(a^2+b^2\) is divided by 7?


(1) \(a - b = 4\)

(2) \(a^2b^3\) is divisible by 14

statement 1:
\((a - b)^2 = a^2+b^2-2ab = 16\)
\(a^2+b^2 = 16 - 2ab\)
we do not know values of a,b.
not sufficient

statement 2:
\(a^2b^3 = 2*7*k\)
either a,b or a*b is a multiple of 14
not sufficient

combining both statements,
\(a^2+b^2 = \frac{rem(16 - 2ab)}{14}\) = 2

\(a^2+b^2 = 16 + 2ab \)
\(not 16 - 2ab \)
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Kritisood
If a and b are integers then what is the remainder when \(a^2+b^2\) is divided by 7?


(1) \(a - b = 4\)

(2) \(a^2b^3\) is divisible by 14


(1) \(a - b = 4\)
We are asked about \(a^2+b^2\), so can we convert a-b in this form.
\((a-b)^2=4^2........a^2+b^2-2ab=16........a^2+b^2=16+2ab\)
So we are looking for the remainder when 16+2ab is divided by 7.
But we do not know what is ab.
Insufficient

(2) \(a^2b^3\) is divisible by 14
As a and b are integers, at least one of a or b is surely divisible by 7, that is ab=7x
But we cannot work further for the value of a^2+b^2.
Insufficient


Combined
16+2ab=16+7x=2+14+7x will give a remainder 2 when the term is divided by 7.
Sufficient


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