sanjnadhingra
TestPrepUnlimited
itachiuchiha
A group of 10 workers can plough a field in 20 days. This group starts the work and after every 2 days, 2 additional workers join the group. The efficiency of each worker is the same. On which day do the workers finish ploughing the field?
A. 7
B. 8
C. 13
D. 10
E. 11
Here it may be easier to use percentages to compute the amount of days. A single worker would need 200 days to complete the job, so the rate of a single worker is 1/200 = 0.5%.
The combined rate in the beginning would be 5% per day, and we add 1% every two days since we get 2 more workers every day.
Then we can start adding two days at a time until we reach 100%: \(10% + 12% + 14% + 16% + 18% = 70%\) Add another 20% and the next day of 11% to reach 100%.
In total that took 2*5 + 2 + 1 = 13 days.Ans: C
Unsure how you came to that number from the last bit (highlighted in red). Could you please help
TestPrepUnlimited?
Sure, remember that our rate increases every two days.
Our first two days would be 5% + 5%, of the entire task. The next two days would complete 6% + 6% of the entire task.
I am grouping these rates two days at a time now to speed up our calculations, so let's just focus on hitting 100% first. Then we need 5% + 5% + 6% + 6% + 7% .... and I did 10% + 12% + 14% + 16% + 18% = 70% to start off, we're still missing 30%.
The next days will complete 10%, 10%, 11%, 11% 12% ..... so I need three more days of work to finish off the missing 30%.
Now finally if we start counting the number of days used, 10%, 12%, 14%, 16%, 18%, and 20%, each of these percentages represents two days of work. That's 12 days which completes 90% of the work in total, and we need one more day of work so 13 days in total would be enough.
Feel free to ask any more questions!