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505-555 (Easy)|   Graphs|               
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parkhydel
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The graph indicates, for each of the years 1993, 1998, and 2003, the p Updated on: 13 May 2025, 10:21
Originally posted by parkhydel on 09 Jul 2020, 21:54.
Last edited by Bunuel on 13 May 2025, 10:21, edited 3 times in total.
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Dropdown 1: 1993 Dropdown 2: 0.6
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The graph indicates, for each of the years 1993, 1998, and 2003, the percent of the total number of tourists visiting Island X during each of those years by the length of those tourists’ stays on the island.

Based on the assumption that the information provided is correct, select from each drop-down menu the option that completes the statement most accurately.

The combined probability that a tourist chosen at random had stayed either 7 or 14 days on the island was highest in and, to the nearest tenth, that probability was .



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Dropdown 1: 1993 Dropdown 2: 0.6
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The graph indicates, for each of the years 1993, 1998, and 2003, the p 10 Jul 2020, 08:46
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1)1993, Since per the graph there is a peak for 14 days in year 1993 and peak for 7 days in 2003, but if we see the cumulative results,then the highest peak in 1993 for 14 days,makes the overall result for 1993

2)0.6, since the probability for 14 days in 1993= ,50/100= 0.5 and for 7 days in 1993= 12/100=0.12 sotl total is .5+.12= .62~ 0.6

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The graph indicates, for each of the years 1993, 1998, and 2003, the p 07 Nov 2020, 14:06
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The combined probability that a tourist chosen at random had stayed either 7 or 14 days on the island was highest :
1.Check the probability for stay at 7th day and 14th day. Since, the question says OR..Add these 2 probabilities.
2. This does not mean to find the average of all probabilities.
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The graph indicates, for each of the years 1993, 1998, and 2003, the p 05 Apr 2021, 08:42
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Official Explanation

RO1

According to the graph, approximately 12% of the tourists in 1993 stayed on the island for 7 days, and 50% stayed for 14 days. Thus, 12%+50%=62% of the tourists in 1993 stayed on the island for either 7 or 14 days. In 1998, 16% of tourists stayed 7 days and 25% stayed 14 days, for a combined total of 16%+25%=41%. In 2003, 22% of tourists stayed 7 days and 15% stayed 14 days, for a combined total of 22%+15%=37%. Therefore, the percentage of tourists who stayed for either 7 or 14 days is greater in 1993 (62%) than in 1998 (41%) or 2003 (37%), making the probability that a randomly chosen tourist stayed 7 or 14 days greatest in that year.

The correct answer is 1993.

RO2

As explained in the analysis of RO1, 62% of the tourists in 1993 stayed on the island for either 7 or 14 days. Therefore, the combined probability that a randomly chosen tourist that year stayed 7 or 14 days is 0.62, which rounded to the nearest tenth is 0.6.

The correct answer is 0.6.
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The graph indicates, for each of the years 1993, 1998, and 2003, the p 08 Nov 2025, 04:44
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Why are we adding the 2 probabilites here?
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Bunuel
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The graph indicates, for each of the years 1993, 1998, and 2003, the p 08 Nov 2025, 05:50
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amol2807
Why are we adding the 2 probabilites here?
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They’re mutually exclusive events. A tourist can’t stay both 7 and 14 days, so the total probability is P(7) + P(14).
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The graph indicates, for each of the years 1993, 1998, and 2003, the p 07 Aug 2026, 08:36
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For the first option the graph's highest point is when 1993's black line is on 14 days which is the year 1993.
At this time the probability is 50/100 and for 7 days the Probability is around 12/100 or 13/100. which is around 0.12. Adding these two P(14) and P(7) we get the P around 0.62 which is nearest to 0.6
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The graph indicates, for each of the years 1993, 1998, and 2003, the p 12 Aug 2026, 06:09
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To find the probability for the second part (rounded to the nearest tenth):

Read the values for 1993 (the highest year):
• 7-day stay: approx. 13% (0.13)
• 14-day stay: approx. 50% (0.50)

Understand "Combined Probability":

"Combined probability of 7 OR 14 days" does NOT mean adding every point on the graph. (Though all points for a given year do add up to 100% total.) It simply means adding the probabilities of those two specific outcomes together:

Combined Probability = P(7 days) + P(14 days)

0.13 + 0.50 = 0.63

Round to the nearest tenth:

0.63 rounded to the nearest tenth = 0.6
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