The graph indicates, for each of the years 1993, 1998, and 2003, the p

Question

https://gmatclub.com/forum/download/file.php?mode=view&id=55882 The graph indicates, for each of the years 1993, 1998, and 2003, the percent of the total number of tourists visiting Island X during each of those years by the length of those tourists’ stays on the island. Based on the assumption that the information provided is correct, select from each drop-down menu the option that completes the statement most accurately. The combined probability that a tourist chosen at random had stayed either 7 or 14 days on the island was highest in GRAPH_1_PLACEHOLDER and, to the nearest tenth, that probability was GRAPH_2_PLACEHOLDER . 124.jpg

Sajjad1994 · Accepted Answer

Official Explanation

RO1

According to the graph, approximately 12% of the tourists in 1993 stayed on the island for 7 days, and 50% stayed for 14 days. Thus, 12%+50%=62% of the tourists in 1993 stayed on the island for either 7 or 14 days. In 1998, 16% of tourists stayed 7 days and 25% stayed 14 days, for a combined total of 16%+25%=41%. In 2003, 22% of tourists stayed 7 days and 15% stayed 14 days, for a combined total of 22%+15%=37%. Therefore, the percentage of tourists who stayed for either 7 or 14 days is greater in 1993 (62%) than in 1998 (41%) or 2003 (37%), making the probability that a randomly chosen tourist stayed 7 or 14 days greatest in that year.

The correct answer is 1993.

RO2

As explained in the analysis of RO1, 62% of the tourists in 1993 stayed on the island for either 7 or 14 days. Therefore, the combined probability that a randomly chosen tourist that year stayed 7 or 14 days is 0.62, which rounded to the nearest tenth is 0.6.

The correct answer is 0.6.

nkme2007 · Answer

The largest peak is observed for 14 days in 1993.

Hence, the combined probability is higher for 1993 (First Blank)
And, the cumulated probability is just above 60% (Second Blank)

Apt0810 · Answer

1)1993, Since per the graph there is a peak for 14 days in year 1993 and peak for 7 days in 2003, but if we see the cumulative results,then the highest peak in 1993 for 14 days,makes the overall result for 1993

2)0.6, since the probability for 14 days in 1993= ,50/100= 0.5 and for 7 days in 1993= 12/100=0.12 sotl total is .5+.12= .62~ 0.6

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gmatsupermann · Answer

The combined probability that a tourist chosen at random had stayed either 7 or 14 days on the island was highest :
1.Check the probability for stay at 7th day and 14th day. Since, the question says OR..Add these 2 probabilities.
2. This does not mean to find the average of all probabilities.

amol2807 · Answer

Why are we adding the 2 probabilites here?

Bunuel · Answer

They’re mutually exclusive events. A tourist can’t stay both 7 and 14 days, so the total probability is P(7) + P(14).

MANASH94 · Answer

For the first option the graph's highest point is when 1993's black line is on 14 days which is the year  1993. 
At this time the probability is 50/100 and for 7 days the Probability is around 12/100 or 13/100. which is around 0.12. Adding these two P(14) and P(7) we get the P around 0.62 which is nearest to  0.6

dhairya18 · Answer

To find the probability for the second part (rounded to the nearest tenth):

Read the values for 1993 (the highest year):
• 7-day stay: approx. 13% (0.13)
• 14-day stay: approx. 50% (0.50)

Understand "Combined Probability":

"Combined probability of 7 OR 14 days" does NOT mean adding every point on the graph. (Though all points for a given year do add up to 100% total.) It simply means adding the probabilities of those two specific outcomes together:

Combined Probability = P(7 days) + P(14 days)

0.13 + 0.50 = 0.63

Round to the nearest tenth:

0.63 rounded to the nearest tenth = 0.6

The graph indicates, for each of the years 1993, 1998, and 2003, the p

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The graph indicates, for each of the years 1993, 1998, and 2003, the p

Prep Toolkit

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