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Dropdown 1: 1993
Dropdown 2: 0.6
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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80% (01:50) correct
20%
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wrong
based on 1227
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The graph indicates, for each of the years 1993, 1998, and 2003, the percent of the total number of tourists visiting Island X during each of those years by the length of those tourists’ stays on the island.
Based on the assumption that the information provided is correct, select from each drop-down menu the option that completes the statement most accurately.
The combined probability that a tourist chosen at random had stayed either 7 or 14 days on the island was highest in and, to the nearest tenth, that probability was .
Attachment:
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Official Answer
Dropdown 1: 1993
Dropdown 2: 0.6
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05 Apr 2021, 08:42
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Official Explanation
RO1
According to the graph, approximately 12% of the tourists in 1993 stayed on the island for 7 days, and 50% stayed for 14 days. Thus, 12%+50%=62% of the tourists in 1993 stayed on the island for either 7 or 14 days. In 1998, 16% of tourists stayed 7 days and 25% stayed 14 days, for a combined total of 16%+25%=41%. In 2003, 22% of tourists stayed 7 days and 15% stayed 14 days, for a combined total of 22%+15%=37%. Therefore, the percentage of tourists who stayed for either 7 or 14 days is greater in 1993 (62%) than in 1998 (41%) or 2003 (37%), making the probability that a randomly chosen tourist stayed 7 or 14 days greatest in that year.
The correct answer is 1993.
RO2
As explained in the analysis of RO1, 62% of the tourists in 1993 stayed on the island for either 7 or 14 days. Therefore, the combined probability that a randomly chosen tourist that year stayed 7 or 14 days is 0.62, which rounded to the nearest tenth is 0.6.
The correct answer is 0.6.
RO1
According to the graph, approximately 12% of the tourists in 1993 stayed on the island for 7 days, and 50% stayed for 14 days. Thus, 12%+50%=62% of the tourists in 1993 stayed on the island for either 7 or 14 days. In 1998, 16% of tourists stayed 7 days and 25% stayed 14 days, for a combined total of 16%+25%=41%. In 2003, 22% of tourists stayed 7 days and 15% stayed 14 days, for a combined total of 22%+15%=37%. Therefore, the percentage of tourists who stayed for either 7 or 14 days is greater in 1993 (62%) than in 1998 (41%) or 2003 (37%), making the probability that a randomly chosen tourist stayed 7 or 14 days greatest in that year.
The correct answer is 1993.
RO2
As explained in the analysis of RO1, 62% of the tourists in 1993 stayed on the island for either 7 or 14 days. Therefore, the combined probability that a randomly chosen tourist that year stayed 7 or 14 days is 0.62, which rounded to the nearest tenth is 0.6.
The correct answer is 0.6.
General Discussion
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09 Jul 2020, 22:14
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SajjadAhmad
The largest peak is observed for 14 days in 1993.
Hence, the combined probability is higher for 1993 (First Blank)
And, the cumulated probability is just above 60% (Second Blank)
