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Bunuel
If S is the product of integers from 100 to 300 inclusive, and if T is the product of integers 100 to 301, inclusive, what is \(\frac{1}{S} + \frac{1}{T}\) in terms of T?


A. \(\frac{3012}{T}\)

B. \(\frac{(302T)}{301}\)

C. \(302T\)

D. \(\frac{302}{T}\)

E. \((302)(301)T^2\)


S=100x101x102x103x104 ......... x 300.
T=100x101x102x103x104 ......... x 300x 301.
T= Sx301
T/301 = S
1/S = 301/T

1/S + 1/T = 301/T + 1/T = 302/T

Therefore correct answer D.
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Bunuel
If S is the product of integers from 100 to 300 inclusive, and if T is the product of integers 100 to 301, inclusive, what is \(\frac{1}{S} + \frac{1}{T}\) in terms of T?


A. \(\frac{3012}{T}\)

B. \(\frac{(302T)}{301}\)

C. \(302T\)

D. \(\frac{302}{T}\)

E. \((302)(301)T^2\)

S=100*101*.........*300

T=100*101*........300*301

So, T=S*301, or, \(S=\frac{T}{301}\)

So, \(\frac{1}{T}+\frac{1}{S}\)

\(=\frac{1}{T}+\frac{301}{T}\) [Putting the value of S]

\(=\frac{302}{T}\)

The answer is \(D\)
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