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20 Apr 2021, 01:30
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D
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Difficulty:
55%
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Question Stats:
57% (01:52) correct
43%
(01:57)
wrong
based on 99
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The perimeter of a polygon is 16. If the sides of the polygon are all of integer length, the shortest side of the polygon is 2 and the longest side of the polygon is 5, then the number of sides of the polygon could be any number from
A. 3 to 6
B. 4 to 5
C. 3 to 7
D. 4 to 6
E. 4 to 7
A. 3 to 6
B. 4 to 5
C. 3 to 7
D. 4 to 6
E. 4 to 7
20 Apr 2021, 06:37
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The perimeter of a polygon is 16. If the sides of the polygon are all of integer length, the shortest side of the polygon is 2 and the longest side of the polygon is 5, then the number of sides of the polygon could be any number from
A. 3 to 6
B. 4 to 5
C. 3 to 7
D. 4 to 6
E. 4 to 7
Let sides be A1,A2,A3........
16=2+5+A1+A2.....
9 =A1+A2...........
Since shortest side is 2 and longest is 5, 2<= A<=5 ( other sides are any number from 2 to 5)
possible combinations are
4+5 +2+5 = 16
5+2+2+2+5 =16
3+2+2+2+2+5 = 16
no of sides can be 4 to 6 Ans is D
A. 3 to 6
B. 4 to 5
C. 3 to 7
D. 4 to 6
E. 4 to 7
Let sides be A1,A2,A3........
16=2+5+A1+A2.....
9 =A1+A2...........
Since shortest side is 2 and longest is 5, 2<= A<=5 ( other sides are any number from 2 to 5)
possible combinations are
4+5 +2+5 = 16
5+2+2+2+5 =16
3+2+2+2+2+5 = 16
no of sides can be 4 to 6 Ans is D
ramlala
Joined: 22 Aug 2020
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Location: India
Concentration: International Business, Finance
Schools: IIMA PGPX'23 INSEAD Jan'23 intake Sloan (MIT) ISB HEC Said
GPA: 4
WE:Project Management (Energy)
20 Apr 2021, 09:23
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Bunuel
2 sides are 2 and 5 = 7
Remaining sides = 16-7 = 9
Minimum sides = 5 & 4 so total = 2+2 = 4
Maximum sides = 2, 2, 2, 3 so total = 4+2 = 6
Ans: 4 to 6 = D
