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27 Apr 2021, 05:45
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
65% (02:29) correct
35%
(02:27)
wrong
based on 311
sessions
History
Date
Time
Result
Not Attempted Yet
If 10 men or 18 boys can do a piece of work in 15 days, then 25 men and 15 boys together will do twice the work in:
(A) 4 1/2 days
(B) 9 days
(C) 8 days
(D) 32 days
(E) 36 days
(A) 4 1/2 days
(B) 9 days
(C) 8 days
(D) 32 days
(E) 36 days
27 Apr 2021, 12:01
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10 Men = 18 Boys
25 men = 45 Boys
18 Boys can do a work in 15 days
60 Boys (45 + 15) will do the work in \(\frac{(18 * 15)}{60} \)days = \(\frac{9}{2 }\)days
and twice the work in 9 days.
The answer will be B
25 men = 45 Boys
18 Boys can do a work in 15 days
60 Boys (45 + 15) will do the work in \(\frac{(18 * 15)}{60} \)days = \(\frac{9}{2 }\)days
and twice the work in 9 days.
The answer will be B
23 Jul 2021, 06:42
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Bookmarks
Bunuel
Solution:
If we let m = the rate of one man per day and b = the rate of one boy per day, we can create the equation:
10m = 1/15 and 18b = 1/15
m = 1/150 and b = 1/270
Therefore, the rate of 25 men and 15 boys per day is:
25(1/150) + 15(1/1270) = 1/6 + 1/18 = 4/18 = 2/9
So they can complete twice the work in 2/(2/9) = 9 days.
Answer: B
