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12 May 2021, 03:15
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
55% (01:48) correct
45%
(01:50)
wrong
based on 193
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Date
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Not Attempted Yet
Dawn chases her young brother Paul. She runs at a constant speed, six times as fast as he does. After Dawn overtakes Paul, she goes on running at the same speed for two more minutes, and then stops and waits for Paul to reach her. If Paul maintains his constant speed throughout the chase, how many minutes does Dawn wait for Paul?
A. 5
B. 6
C. 8
D. 10
E. 12
A. 5
B. 6
C. 8
D. 10
E. 12
14 May 2021, 00:51
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Okay, so this is a quick random attempt. Please correct me if I'm wrong.
We know Dawn runs 6x fast as Paul does We start calculating time from the point Dawn is at the same point as Paul. So we first need to calculate the distance covered by Dawn in the 2 mins.
Dd=Sd*td
= 6*Sp*2 = 12Sp
So 12Sp is the distance Paul needs to cover in time t secs.
Dp= Sp*t
The distance Paul needs to cover is already found out. i.e 12Sp
So, time taken by Paul to cover 12Sp distance is given by
t=Dp/Sp
=12Sp/Sp
=12min. ----(1)
But we also need to calc the distance travelled by Paul in time = 2sec
Dp = Sp*2
Therefore the total distance he must cover to reach his sister
=12Sp-2Sp = 10Sp
So we have 10Sp/Sp = 10Min
Thoughts ????
We know Dawn runs 6x fast as Paul does We start calculating time from the point Dawn is at the same point as Paul. So we first need to calculate the distance covered by Dawn in the 2 mins.
Dd=Sd*td
= 6*Sp*2 = 12Sp
So 12Sp is the distance Paul needs to cover in time t secs.
Dp= Sp*t
The distance Paul needs to cover is already found out. i.e 12Sp
So, time taken by Paul to cover 12Sp distance is given by
t=Dp/Sp
=12Sp/Sp
=12min. ----(1)
But we also need to calc the distance travelled by Paul in time = 2sec
Dp = Sp*2
Therefore the total distance he must cover to reach his sister
=12Sp-2Sp = 10Sp
So we have 10Sp/Sp = 10Min
Thoughts ????
Westfolia007
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Joined: 02 May 2021
Last visit: 21 Jun 2025
Posts: 22
Given Kudos: 11
Location: India
Schools: ESSEC MiM "24 (A)
GMAT 1: 690 Q48 V36
16 May 2021, 07:11
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Once Dawn is at par with Paul, she will cover a relative distance of {2 minutes * (6x -x)} ; 6x and x are the respective speeds
Relative distance = 10x
Speed of Paul = x
Time = 10x/x = 10 minutes
Option D
Relative distance = 10x
Speed of Paul = x
Time = 10x/x = 10 minutes
Option D
