It's a bit of a strange question, and there are a few ways to break it down, but inspection works well. If, from Statement 1, the two numbers add up to 180-something, one of the numbers must be 90 or greater (their average is greater than 90, and the two numbers can't both be below average). So one of our digits is 9. But if the other digit was 7, our sum wouldn't be big enough, and if the other digit was 9, the sum would be too large, so our digits must be 9 and 8, and their product is 72, so Statement 1 is sufficient.
Statement 2 will be true any time we have to carry 1 when we add, so our numbers could be 65 and 56, say, or 85 and 58, among other possibilities, and the answer is A.
You can also write things algebraically: the two-digit number AB is equal to 10A + B. So the sum in Statement 1 is equal to 10A + B + 10B + A = 11A + 11B = 11(A + B), and this is a multiple of 11. If that equals some number in the 180s, it must equal 187, the only multiple of 11 between 180 and 189, so 11(A+B) = 187, and A+B = 17. Since A and B are single-digit integers, they can only be 8 and 9. So Statement 1 is sufficient.