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nikhilvarekar
chetan2u
If x is a positive integer greater than 3, is x equal to 7?

1) \(x^4 − 3^4=(x^2-3^2)(x^2+3^2)=(x-3)(x+3)(x^2+9)\) is divisible by 29
When x=7, \((7+3)(7-3)(7^2+9)=10*4*58\). Since, it is divisible by 29, so x can be 7.
But, when x is 10, then too \((10+3)(10-3)(10^2+9)=13*7*109\) is divisible by 29.
Insufficient

E

chetan2u,

13*7*109= 9919, whereas 29*342=9918. Am i missing something here? I think the answer should be A. Please share your thoughts.


Yes, x should not be 10, but it here can be so many other values that can fit here.
(x+3)(x-3)((x^2+9) is divisible by 29.
When x is 32, 32-3 is 29 but 32 is not divisible by 7
(32+3)(32-3)(32^2+9)=35*29*(32^2+9)
When x is 61, 61-3 is 58 but 58 is not divisible by 7
(61+3)(61-3)(61^2+9)=64*58*(61^2+9)
and so on.
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