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16 Sep 2021, 07:15
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C
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Difficulty:
35%
(medium)
Question Stats:
70% (01:27) correct
30%
(01:40)
wrong
based on 109
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There are four positive integers x, y, z and w. If x/y leaves a remainder 3 and w/z leaves a remainder 8, what is the smallest possible value for y+z ?
(A) 11
(B) 12
(C) 13
(D) 14
(E) 15
(A) 11
(B) 12
(C) 13
(D) 14
(E) 15
Updated on: 16 Sep 2021, 09:24
Originally posted by BrentGMATPrepNow on 16 Sep 2021, 08:11.
Last edited by BrentGMATPrepNow on 16 Sep 2021, 09:24, edited 1 time in total.
Last edited by BrentGMATPrepNow on 16 Sep 2021, 09:24, edited 1 time in total.
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Bunuel
Key property:
When positive integer N is divided by positive integer D, the remainder R is such that 0 ≤ R < D
For example, if we divide some positive integer by 7, the remainder will be 6, 5, 4, 3, 2, 1, or 0
If x divided y leaves a remainder of 3, then we know that 0 ≤ 3 < y, which means 4 is the smallest possible value of y
Similarly, if w divided z leaves a remainder of 8, then we know that 0 ≤ 8 < z, which means 9 is the smallest possible value of z
So, the smallest possible value of y + z = 4 + 9 = 13
Answer: C
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StarTrooper
Joined: 14 Sep 2020
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Schools: IIMA PGPX'23
GMAT 1: 710 Q49 V39
16 Sep 2021, 08:26
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BrentGMATPrepNow
Doesn't that makes Z, Z>8, to be 9 as the least value.
and the solution to be 4 + 9 = 13 ?
Regards
